Answer:
5/6
Step-by-step explanation:
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Answer:
5
Step-by-step explanation:
 
        
             
        
        
        
Answer:
1
Step-by-step explanation:
If you are just looking for the derivative, then all you need to use the power rule for this. Technically the x in (x-9) has a power to the 1, so really x^1-9. To use power rule, you bring down the exponent, in this case, 1, and then minus 1 from what the exponent was. 
1x^(1-1) = 1x^0. The derivative of any constant is 0, so don't even worry about the -9. We know that anything raised to the zero is just 1, so in this case your answer is 1. 
Hope this helps :)
 
        
             
        
        
        
Question is Incomplete, Complete question is given below.
Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.
Answer:
∆ABC is right angled triangle with right angle at B.
Step-by-step explanation:
Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.  
We need to prove that triangle is the right angled triangle.
Let the triangle be denoted by Δ ABC with side as;
AB = (a - 1) cm 
BC = (2√ a) cm
CA = (a + 1) cm  
Hence, 
 
 
Now We know that

So;


Now;

Also;

Now We know that




[By Pythagoras theorem]

Hence, 
Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.
This proves that ∆ABC is right angled triangle with right angle at B.
 
        
             
        
        
        
<span>✡ Answer: 9000 </span><span>✡
- - Solve:
If your 3 numbers to the right (in this problem its 3) are 499 or less, you round down, if its 500 or up, you round up.
In this case, round up.
- - Solve furthermore:
          9000
</span>
✡Hope this helps<span>✡</span>