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seropon [69]
3 years ago
8

Need help with 2&3 please .

Mathematics
1 answer:
Vsevolod [243]3 years ago
5 0

Answer:

brainly.com/question/12500028

Step-by-step explanation:

brainly.com/question/12500028

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0.5x+3.5=6 what is x
nasty-shy [4]

Answer:

5

Step-by-step explanation:

0.5x=6-3.5

0.5x=2.5

x=2.5÷0.5

x=5

6 0
3 years ago
Read 2 more answers
HELP <br> Write an equation that represents the line.<br> Use exact numbers.
horrorfan [7]
Y=7/5+6.8

I believe it can a little more than 6.8 but either way this is correct
3 0
2 years ago
Solve the equation<br> 6.7x = 5.2x + 12.3
Anna [14]

Answer:

x = 8.2

Step-by-step explanation:

6.7x = 5.2x + 12.3

6.7x - 5.2x = 12.3

1.5x = 12.3

x = 8.2 =  \frac{41}{5}  = 8 \frac{1}{5}

7 0
3 years ago
6. trapezoid ABCD shown below, AB|| DC, overline BC perp overline DC and sides have lengths as shown (aDetermine the measure of
laila [671]

Answer:

a). ∠D = 56°

b). AD = √13

Step-by-step explanation:

(a) From the figure attached, ABCD is a trapezoid with parallel sides AB and CD. We have to find the measure of ∠D from the given figure.

From triangle ADE,

tanD=\frac{AE}{DE}

         =\frac{3}{2}

D = tan^{-1}(1.5)

D = 56.31

D ≈ 56°

Therefore, measure of ∠D is 56°.

(b). Now by applying Pythagoras theorem in ΔADE,

AD² = AE² + DE²

       = 3² + 2²

AD² = 9 + 4

AD = √13

Length of AD is √13 in.

7 0
3 years ago
If the numbers 4, 5 and 6 are each used exactly once to replace the letters in the expression A ( B − C ), what is the least pos
guapka [62]

Answer:

The least possible result is <em>-10</em>.

Step-by-step explanation:

Given the numbers 4, 5 and 6 are to be chosen one of the letters A, B or C.

First of all,

Let A = 4, B = 5 and C = 6

A(B-C) = 4 \times (5-6) = 4 \times -1 = -4

Let A = 4, B = 6 and C = 5

A(B-C) = 4 \times (6-5) = 4 \times 1 = 4

Let A = 5, B =4 and C = 6

A(B-C) = 5 \times (4-6) = 5 \times -2 = -10

Let A = 5, B = 6 and C = 4

A(B-C) = 4 \times (6-4) = 4 \times 2 = 8

Let A = 6, B = 4 and C = 5

A(B-C) = 6 \times (4-5) = 6 \times -1 = -6

Let A = 6, B = 5 and C = 4

A(B-C) = 6 \times (6-5) = 6 \times 1 = 6

Summarizing the above values in the form of a table:

\begin{center}\begin{tabular}{ c c c c}A & B & C & A(B-C)\\ 4 & 5 & 6 & -4\\  4 & 6 & 5 & 4\\  5 & 4 & 6 & -10\\  5 & 6 & 4 & 10\\  6 & 4 & 5 & -6\\ 6 & 5 & 4 & 6\end{tabular}\end{center}

So, the least possible result is <em>-10</em>.

3 0
3 years ago
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