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andreev551 [17]

3 years ago

9

If one letter is chosen at random from the word comb what is the probability that the letter chosen will be a b

1 answer:

STatiana [176]3 years ago

7 0

The word comb has 4 total letters and there is one b

the probability would be the number of B's over the total number of letters in the word

the answer would be 1/4 probability

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In triangle EFG , EF=FG . EF= 6X-10 , EG =2X+14, and FG =3X+11. find EF .

jarptica [38.1K]

Since EF=FG, you can set 6x - 10 = to 3x + 11

$6x -10 = 3x +11$

Then add like terms

$6x - 3x = 11+10$

so, $3x = 21$

Now you can divide by 3 to get $x = 7$ :)

then put it back into $6x - 10$

$6(7) - 10 = EF$

so, $EF = 32$

4 0

3 years ago

Given: PRST is a square

xxTIMURxx [149]

Answer:

$(1-\sqrt{2})a^2$

Step-by-step explanation:

Consider irght triangle PRS. By the Pythagorean theorem,

$PS^2=PR^2+RS^2\\ \\PS^2=a^2+a^2\\ \\PS^2=2a^2\\ \\PS=\sqrt{2}a$

Thus,

$MS=PS-PM=\sqrt{2}a-a=(\sqrt{2}-1)a$

Consider isosceles triangle MSC. In this triangle

$MS=MC=(\sqrt{2}-1)a.$

The area of this triangle is

$A_{MSC}=\dfrac{1}{2}MS\cdot MC=\dfrac{1}{2}\cdot (\sqrt{2}-1)a\cdot (\sqrt{2}-1)a=\dfrac{(\sqrt{2}-1)^2a^2}{2}=\dfrac{(3-2\sqrt{2})a^2}{2}$

Consider right triangle PTS. The area of this triangle is

$A_{PTS}=\dfrac{1}{2}PT\cdot TS=\dfrac{1}{2}a\cdot a=\dfrac{a^2}{2}$

The area of the quadrilateral PMCT is the difference in area of triangles PTS and MSC:

$A_{PMCT}=\dfrac{(3-2\sqrt{2})a^2}{2}-\dfrac{a^2}{2}=\dfrac{(2-2\sqrt{2})a^2}{2}=(1-\sqrt{2})a^2$

5 0

3 years ago

What is 100×3857×29473

marshall27 [118]

The answer is 11367736100!

3 0

3 years ago

Read 2 more answers

Can you help me figure out if my this answer is correct...<br> 3(4x+ 5y +6)= 12×+15y+18

svetlana [45]

Answer: Yes, well done.

Step-by-step explanation:

$3(4x+5y+6)=12x+15y+18\\(3*4x)+(3*5y)+(3*6)=12x+15y+18\\12x+15y+18=12x+15y+18$

6 0

4 years ago

Given ABC is similar to DEF and BC = 8, what is the value of EF?

lbvjy [14]

In similar triangles ratios of corresponding sides are constant, so

|AB|/|DE| = |BC|/|EF|

5/10 = 8/|EF|

|EF| = (8*10)/5 = 16

|EF| = 16

6 0

3 years ago