The ratio of the lengths of the corresponding sides of triangle ABC to triangle DEF is 2:3, and since side AC is the corresponding side of side DF -> Side DF = 3/2 side AC-> Side DF = 2.5 x 3/2 = 3.75 cm.
Distance = sqrt(5- -6)^2 + (3- -6)^2)
= sqrt (121 + 81)
= sqrt 202
= 14.21 to nearest hundredth
The answer is 51 Meters. I subtracted the man from the building and it's 51 meters.
Answer:
128 banana's... I would work it all out for u but the teacher just came in my room and had a go
Step-by-step explanation: