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Wewaii [24]
4 years ago
13

(1/3+9)*(8-3) in a fraction

Mathematics
1 answer:
neonofarm [45]4 years ago
6 0
1/3+9=(9 1/3)
8-3= (5)
9*5=45 add the 1/3 back in 
45 1/3 for the fraction take 45*3=135+1= 136/3
136/3 is the answer
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A truck that is 10 ft. by 10 ft. by 14 ft. carries boxes that are 2 ft. by 2 ft. by
lianna [129]

The number of boxes that the truck can hold if it is already 65% full is; 49 boxes

<h3>Volume of a truck </h3>

We are given the truck dimensions as;

  • Length; L = 10 ft
  • Width; w = 10 ft
  • Height; h = 14 ft

Formula for volume of truck is;

V = L × w × h

Thus;

V_truck = 10 × 10 × 14

V_truck = 1400 ft³

Volume of boxes is;

V_box = 2 × 2 × 2.5

V_box = 10 ft³

We are told that truck is 65% full.

Thus;

Volume left in truck = 35% × 1400

Volume left in truck = 490 ft³

Thus;

Number of boxes the truck can hold at the 65% capacity = 490/10 = 49 boxes

Read more on volume of a box at; brainly.com/question/15532376

8 0
3 years ago
PLSSSS HELLLPPP WILL GIVE BRAINLIESTTT!!!!!!!!!
Lerok [7]

Answer: -3/2

Step-by-step explanation:

There are two methods to find the slope

METHOD 1. Rise/Run

Rise: the y-axis value

Run: the x-axis value

In the graph, rise/run=3/2

The line is going down, so it should be negative

-3/2

Hope this helps!! :)

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5 0
3 years ago
A teacher believes that the third homework assignment is a key predictor in how well students will do on the midterm. Let x repr
Darina [25.2K]

Answer:

Hello your question has a disjointed equation attached to it and it is also incomplete attached below is the correct and complete question

A teacher believes that the third homework assignment is a key predictor in how well students will do on the midterm. Let x represent the third homework score and y the midterm exam score. A random sample of last terms students were selected and their grades are shown below

answer :

y-intercept = 25.9047

 slope = 2.8420

Step-by-step explanation:

Determine the slope for the regression equation and y intercept

The regression equation ( gotten using excel ; attached below is the excel sample on how the equation was gotten )

y = 25.9047 + 2.8420x

from the equation gotten above

y-intercept = 25.9047

slope = 2.8420

4 0
3 years ago
Base: z(x)=cosx Period:180 Maximum:5 Minimum: -4 What are the transformation? Domain and Range? Graph?
garik1379 [7]

Answer:

The transformations needed to obtain the new function are horizontal scaling, vertical scaling and vertical translation. The resultant function is z'(x) = \frac{1}{2}  + \frac{9}{2} \cdot \cos \left(\frac{\pi\cdot x}{90^{\circ}} \right).

The domain of the function is all real numbers and its range is between -4 and 5.

The graph is enclosed below as attachment.

Step-by-step explanation:

Let be z (x) = \cos x the base formula, where x is measured in sexagesimal degrees. This expression must be transformed by using the following data:

T = 180^{\circ} (Period)

z_{min} = -4 (Minimum)

z_{max} = 5 (Maximum)

The cosine function is a periodic bounded function that lies between -1 and 1, that is, twice the unit amplitude, and periodicity of 2\pi radians. In addition, the following considerations must be taken into account for transformations:

1) x must be replaced by \frac{2\pi\cdot x}{180^{\circ}}. (Horizontal scaling)

2) The cosine function must be multiplied by a new amplitude (Vertical scaling), which is:

\Delta z = \frac{z_{max}-z_{min}}{2}

\Delta z = \frac{5+4}{2}

\Delta z = \frac{9}{2}

3) Midpoint value must be changed from zero to the midpoint between new minimum and maximum. (Vertical translation)

z_{m} = \frac{z_{min}+z_{max}}{2}

z_{m} = \frac{1}{2}

The new function is:

z'(x) = z_{m} + \Delta z\cdot \cos \left(\frac{2\pi\cdot x}{T} \right)

Given that z_{m} = \frac{1}{2}, \Delta z = \frac{9}{2} and T = 180^{\circ}, the outcome is:

z'(x) = \frac{1}{2}  + \frac{9}{2} \cdot \cos \left(\frac{\pi\cdot x}{90^{\circ}} \right)

The domain of the function is all real numbers and its range is between -4 and 5. The graph is enclosed below as attachment.

8 0
3 years ago
What are all of these?
serious [3.7K]
They are abstract "word" problems, offered for the purpose of giving the
student of high school mathematics valuable practice in the application
and manipulation of the concept of "percent". 

Often, some time spent in solving practice-examples such as these can
lead to the phenomenon known as "learning", whereby the student comes
to know, understand, and possess competence in a topic where he or she
was previously ignorant and incompetent. 

It is important to realize that the practice is the vital component in the process,
whereas the answers alone have no value at all.
3 0
3 years ago
Read 2 more answers
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