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MrRissso [65]
3 years ago
10

Jared measured a house and its lot and made a scale drawing. The scale of the drawing was 5 millimeters : 3 meters. The actual l

ength of the front lawn is 69 meters. How long is the lawn in the drawing?
Mathematics
1 answer:
alukav5142 [94]3 years ago
4 0

Answer:

115mm

Step-by-step explanation:

5/x = 3/69

5/x = 1/23

5*23 = x

115 = x

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50.) Find the value of b so that 330_b = 226_b+5<br> URGENT
jekas [21]

Step-by-step explanation:

make equation and find the value

7 0
3 years ago
How do i solve functions?
Maksim231197 [3]
Most quadratic functions(which is what you have there, to a degree of 2) are solved using factoring and the zero product law. If you can not factor then you have to use the quadratic formula or graph it. However this one can be factored.
It's pretty simple to just factor it by inspection but I use the chart method, if you know decomposition that works as well.
Factoring gives us,
(2x + 1)(x - 3) = 0
Then you set each factor to 0 and solve for x,
2x + 1 = 0
2x =  - 1
x =  \frac{ - 1}{2}
And the second one,
x - 3 = 0
x = 3
The solutions to this equation are
x = -1/2, 3
6 0
3 years ago
Similar shapes are always congruent true or false?
ValentinkaMS [17]

Answer:

FALSE

Step-by-step explanation:

4 0
3 years ago
Between the time Iko woke up and lunchtime, the temperature rose by 11°. Then by the time he went to bed, the temperature droppe
Tanzania [10]

Answer:             -3 degrees

Step-by-step explanation:

Lets say that the original temperature was "x."

The temperature rose by 11 degrees so it is now at 11+x.

Then the temperature fell by 14 degrees so you subtract. 11+x-14

11-14= -3 so you subtract 3 degrees from the original temperature and there fore the relative temperature is -3

I hope this helps!!!

4 0
3 years ago
Where should the point P be chosen on line segment AB so as to maximize the angle θ? (Assume a = 4 units, b = 5 units, and c = 9
taurus [48]
From the figure, let the distance of point P from point A on line segment AB be x and let the angle opposite side a be M and the angle opposite side c be N.

Using pythagoras theorem,
\tan M= \frac{a}{b-x} \\ \\ M=\tan^{-1}\left(\frac{a}{b-x}\right)
and
\tan N= \frac{c}{x} \\ \\ N=\tan^{-1}\left(\frac{c}{x}\right)

Angle θ is given by
\theta=180-M-N \\  \\ =180-\tan^{-1}\left(\frac{a}{b-x}\right)-\tan^{-1}\left(\frac{c}{x}\right)

Given that a = 4 units, b = 5 units, and c = 9 units, thus
\theta=180-\tan^{-1}\left(\frac{4}{5-x}\right)-\tan^{-1}\left(\frac{9}{x}\right)

To maximixe angle θ, the differentiation of <span>θ with respect to x must be equal to zero.
i.e.
\frac{d\theta}{dx} = -\frac{4}{x^2-10x+41} + \frac{9}{x^2+81} =0 \\  \\ -4(x^2+81)+9(x^2-10x+41)=0 \\  \\ -4x^2-324+9x^2-90x+369=0 \\  \\ 5x^2-90x+45=0 \\  \\ x^2-18x+9=0 \\  \\ x=9\pm6 \sqrt{2}

Given that x is a point on line segment AB, this means that x is a positive number less than 5.

Thus
x=9-6 \sqrt{2}=0.5147

Therefore, The distance from A of point P, so that </span>angle θ is maximum is 0.51 to two decimal places.
6 0
3 years ago
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