Answer:
first blank = 39
second blank = 28
Step-by-step explanation:
11 + __ + 7 + 28 = 85 = 39 + __ + 11+ 7
since,, four terms add upto form 85 out of which two terms (11 and 7) are common. so, the first blank will be filled with 39 and second blank with 28.
The Unit Rate is the start of the slope/the y-intercept of the slope.To find that we need to make the slope first.
(shown in the first picture)
We can see that the slope is a linear function/a straight line, and if we just follow the line down the slope we can see that it has a y-intercept/unit rate of 2/3 of 1 whole.
(the second picture)
x -y = 1
5x + 3y = 45
Solve the first equation for x: x = y + 1
Substitute x in the second with y + 1
5x + 3y = 45
5(y + 1) + 3y = 45
5y + 5 + 3y = 45
8y + 5 = 45
8y = 40
y = 5
Substitute 5 for y in x = y + 1
x = y + 1
x = 5 + 1
x = 6
Answer: (6, 5)
Answer:
(a)
(b)
(c)
(d)
(e)
(f)
Step-by-step explanation:
Let as consider the given equations are
.
(a)


![[\because \log_aa^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%5Ex%3Dx%5D)
(b)
![[\because \log_aa^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%5Ex%3Dx%5D)
(c)


![[\because \log_aa^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%5Ex%3Dx%5D)
(d)

![[\because \log_aa^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%5Ex%3Dx%5D)
(e)


![[\because \log_aa^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%5Ex%3Dx%5D)
(f)


![[\because \log10^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog10%5Ex%3Dx%5D)