Question

The claim is that the proportion of accidental deaths of the elderly attributable to residential falls is more than 0.10, and the sample statistics include n=800 deaths of the elderly with 15 percent of them attribute to residential falls. find the value of the test statistic... and show work
a 3.96
b. 4.71
c. -3.96
d. -4.71

Answer 1

Answer:

The correct option is b) 4.71

Step-by-step explanation:

Consider the provided information.

Test statistic for proportion: $z=\frac{\hat p-p}{\sqrt{\frac{pq}{n}}}$

It is given that the claim is that the proportion of accidental deaths of the elderly attributable to residential falls is more than 0.10, and the sample statistics include n=800 deaths of the elderly with 15 percent of them attribute to residential falls.

Therefore, $\hat p=0.15$, p = 0.1, q = 1-0.1 = 0.9 and n = 800.

Substitute the respective values in the above formula.

$z=\frac{0.15-0.1}{\sqrt{\frac{0.1\times0.9}{800}}}$

$z=\frac{0.05}{\sqrt{\frac{0.09}{800}}}$

$z\approx4.71$

Hence, the correct option is b) 4.71