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Elina [12.6K]
3 years ago
6

I need the answer ASAP and work

Mathematics
1 answer:
Verdich [7]3 years ago
7 0
The answer is B) 108 cubic inches because since prism H is three times the height of prism G's height , the volume of prism H is three times prism G volume therefore you multiply prism G's height; 36 by 3 to get 108
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Zara has a collection of 4 marbles: an Aggie, a Bumblebee, a Steelie, and a Tiger. She wants to display them in a row on a shelf
KengaRu [80]

Answer:

Step-by-step explanation:

Oops I meant "there are 3! = 6 ways to permute ABTS that have TS."

3 0
3 years ago
What is the answer to this?
a_sh-v [17]
The answer is 35 bc it has pointed on the dot
5 0
4 years ago
The map uses a scale of 1 in = 220 ft. On the map, how many inches<br> represent 1 mile?
ASHA 777 [7]

Answer:

24 inches

Step-by-step explanation:

There are 5280 feet in a mile
There are 220 feet in 1 in on the map

5280/220 = 24

6 0
2 years ago
These figures are similar. What is the length of the missing side, x?
pshichka [43]

Answer:

5 ft

Step-by-step explanation:

the smaller one is 1/3 of the size of the bigger one

3 0
3 years ago
Consider a system with one component that is subject to failure, and suppose that we have 115 copies of the component. Suppose f
castortr0y [4]

Answer:

Step-by-step explanation:

From the given information:

the mean (\mu) = 115 \times 20

= 2300

Standard deviation = 20 \times \sqrt{115}

Standard deviation (SD) = 214.4761

TO find:

a) P(x > 3500)= P(Z > \dfrac{3500-\mu}{214.4761})

P(x > 3500)= P(Z > \dfrac{3500-2300}{214.4761})

P(x > 3500)= P(Z > \dfrac{1200}{214.4761})

P(x > 3500)= P(Z >5.595)

From the Z-table, since 5.595 is > 3.999

P(x > 3500)=1-0.9999

P(x > 3500) = 0.0001

b)

Here, the replacement time for the mean (\mu) = \dfrac{0+0.5}{2}

= 0.25

Replacement time for the Standard deviation \sigma = \dfrac{0.5-0}{\sqrt{12}}

\sigma = 0.1443

For 115 component, the mean time = (115 × 20)+(114×0.25)

= 2300 + 28.5

= 2328.5

Standard deviation = \sqrt{(115\times 20^2) +(114\times (0.1443)^2)}

= \sqrt{(115\times 400) +(114\times 0.02082249}

= \sqrt{(46000) +2.37376386}

= \sqrt{(46000) +(2.37376386)}

= \sqrt{46002.374}

= 214.482

Now; the required probability:

P(x > 4125) = P(Z > \dfrac{4125- 2328.5}{214.482})

P(x > 4125) = P(Z > \dfrac{1796.5}{214.482})

P(x > 4125) = P(Z >8.376)

P(x > 4125) =1-  P(Z

From the Z-table, since 8.376 is > 3.999

P(x > 4125) = 1 - 0.9999

P(x > 4125) = 0.0001

7 0
3 years ago
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