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3 years ago

Help me please ..............................................................

Mathematics

1 answer:

seropon [69]3 years ago

4 0

Answer:

Coplanar

Step-by-step explanation:

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Carlo think he will go to the gym about 20 times a month.Calculate how much each of these options would cost carlo for one month

galben [10]

20 divided by 4 is 5 so

4$ will be for pay as you go.

5$ will be for regular deal

4+5=9 so the all in one deal is 9$

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3 years ago

Chandler is walking 1/16 km every 10 minutes. How many kilometers will he walk in 1 hour?!

SashulF [63]

Answer:

$\frac{3}{8} or\ 0.375\ km$

Step-by-step explanation:

Given: Chandler walk 1/16 km every 10 minutes.

First, lets find how many 10 minutes in one hours or convert minutes in hours.

∴ Time= $\frac{60}{10} \ h$

Now, finding kilometres travelled in 1 hour.

Distance travelled= $\frac{1}{16} \times \frac{60}{10} = \frac{1}{16} \times 6$

Distance travelled = $\frac{3}{8}$

Converting $\frac{3}{8} \ km$ into decimal will have 0.375 km.

∴ $\frac{3}{8} or\ 0.375\ km$ will chandler walk in 1 hour.

7 0

3 years ago

Read 2 more answers

3.14 times 16 divided by 3

AleksAgata [21]

Answer:

The answer is 16.746667

Step-by-step explanation:

1) Simplify 3.14 × 16 to 50.24.

$50.24 \div 3$

2) Simplify 50.24 ÷ 3 to 16.746667.

$16.746667$

Therefor. the answer is 16.746667.

5 0

3 years ago

What equation represents this sentence?

Anna007 [38]

Answer:

3-n=14

Step-by-step explanation less than a number!!! If a number is unkown it would be a variable, a letter,

3 0

2 years ago

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Find the measures of the four numbered angles

Genrish500 [490]

First, find out x
x+15+2x+15=180
3x+30=180
3x=150
x=50
so the two angels are x+15=65(let's name is ∠5 for convenience), and ∠6= 2x+15=115
notice the two inner lines are marked as congruent, so
∠4=∠5=65
∠1=180-∠4-∠5=180-65-65=50
Name the right bottom angle ∠7, ∠3=∠7 and ∠3+∠7=the exterior angle 100 degree, therefore, ∠3=50
∠2+∠3=∠4, therefore, ∠2=∠4-∠3=65-50=15
∠1=50, ∠2=15, ∠3=50, ∠4=65

5 0

3 years ago