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3 years ago

What is the current density of the solution a/m2

Mathematics

1 answer:

Jlenok [28]3 years ago

8 0

Current density of solution a/m2 is given below

Step-by-step explanation:

Current density is the measure of current generated per unit surface area of electrode.

Eg: In microbial fuel cell/fuel cells, if you are using electrode with size of 5cm x 2cm and current produced is 200mA, then current density will be,

CD= Current/(projected area of electrode)

area of rectangle= LxB= 5cm x 2cm =10cm2

CD= 200mA/10cm2

CD= 20mA/cm2

Your Current will be 200mA.

Current density will be 20mA/cm2.

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morpeh [17]

Answer:

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Step-by-step explanation:

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3 years ago

1 What is the slope of the line through (-9,-6) and (3,-9)?

Setler [38]

Answer:

-2/3

Step-by-step explanation:

So the slope of the line that goes through the points and is m=3/2

Now flip the fraction and change the sign to get the answer -2/3

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3 years ago

Read 2 more answers

1. 2x + 4 = 3(x – 2) + 1

sweet [91]

Please, do not post more than 1 or 2 questions at a time. Out of courtesy I will address one of your six questions here:

2x + 4 = 3(x – 2) + 1

You are to solve this for x.

1) perform the multiplication: 2x + 4 = 3x - 6 + 1
2) combine like terms: 4+6-1 = x
3) solve for x: x = 11
4) check: Is 2(11) + 4 = 3(11-2) + 1 true?
Is 22+4 = 33-6 true? NO. Try again, looking for the mistake:

2x + 4 = 3(x – 2) + 1 => 2x + 4 = 3x - 6 + 1
4 = x - 5
9 = x

Check: Is 2(9) + 4 = 3(9-2) + 1 true? Is 18+4 = 22 true? YES.
The solution to #1 is x = 9 (answer).

Submit your other questions separately, please.

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4 years ago

How do I do number 8?

Tatiana [17]

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4 years ago

An aquarium with a square base has no top. There is a metal frame. Glass costs 8 dollars/m^2 and the frame costs 7 dollars/m. Th

Irina-Kira [14]

Given that the volume of the aquarium is 20m^3.

Volume = Area of Base x height

Area of Base = Volume / height = 20/h

Given that the aquarium has a square base.

Area of square = l^2

Thus, the length of the base of the aquarium is $\sqrt{area \ of \ base} = \sqrt{ \frac{20}{h} }$

The frame is to cover 8 sides with the length equal to the length of the base and 4 sides with the length of the height.

Thus, the total perimeter of the frame is given by $8\sqrt{\frac{20}{h}}+4h= \sqrt{64\left(\frac{20}{h}\right)}+4h = \sqrt{\frac{1,280}{h}}+4h$

Area of the four side faces of the aquarium is 4 times the length of the base times the height = $4\times\sqrt{ \frac{20}{h} }\times h=\sqrt{16\left(\frac{20}{h}\right)h^2}=\sqrt{320h}$

Total area to be covered by grass is the base and the four side faces and is given by $\frac{20}{h}+\sqrt{320h}$

Cost of the entire metal frame = $7\left(\sqrt{\frac{1,280}{h}}+4h\right)= \sqrt{49\left(\frac{1,280}{h}\right)}+7(4h) = \sqrt{\frac{62,720}{h}}+28h$

Cost of the entire grass = $8\left(\frac{20}{h}+\sqrt{320h}\right)=\frac{160}{h}+\sqrt{64(320h)}=\frac{160}{h}+\sqrt{20,480h$

Therefore, total cost in terms of the height, h, is given by

$C=\sqrt{\frac{62,720}{h}}+28h+\frac{160}{h}+\sqrt{20,480h$

3 0

3 years ago