What is the current density of the solution a/m2

Mathematics

1 answer:

Jlenok [28]3 years ago

8 0

Current density of solution a/m2 is given below

Step-by-step explanation:

Current density is the measure of current generated per unit surface area of electrode.

Eg: In microbial fuel cell/fuel cells, if you are using electrode with size of 5cm x 2cm and current produced is 200mA, then current density will be,

CD= Current/(projected area of electrode)

area of rectangle= LxB= 5cm x 2cm =10cm2

CD= 200mA/10cm2

CD= 20mA/cm2

Your Current will be 200mA.

Current density will be 20mA/cm2.

You might be interested in

Select the statement that can be represented by −10 dollars.

antiseptic1488 [7]

Answer:

Step-by-step explanation:

6 0

3 years ago

PLESE HELP ME.........

sergiy2304 [10]

1296 is your answer.

3 0

3 years ago

A slide is 21 feet long. To get to the top of the slide, you use a vertical 9-foot high rung ladder. What is the distance, b, fr

mojhsa [17]

Its a right angled triangle. You have C and have B all you need to find is A. usually for a question like this you would use the Pythagorean theorem which is A2+B2=C2 but since we already have c we will use C2-B2=A2
Now we fill in the values. (21)2-(9)2=A2
441-81=360^2 so now with the 360^2 we have to squareroot it so the square root of 360 is 18.973f

3 0

4 years ago

What kind of shift does the graph have? y = -sin (x-1) from y = sin(x)

Mademuasel [1]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}}
\\\\
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\\\
f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}}
\end{array}
\\\\
-------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{ A}}|\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\$

$\bf \bullet \textit{vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period or frequency}\\
\left. \qquad \right. \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\left. \qquad \right. \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)$

now, with that template in mind, let's see

$\bf \begin{array}{lllll}
y=&-1sin(&1x&-1)&+0\\
&A&B&C&D
\end{array}
\\\\\\
\textit{horizontal shift of }\cfrac{C}{B}\implies \cfrac{-1}{1}\implies -1
\\\\\\
\textit{A is negative, so is flipped upside-down}$

8 0

3 years ago

Given that WXYZ is a rectangle and ZY=2x + 3, and WX=x +4, then WX=

omeli [17]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers