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nydimaria [60]
3 years ago
7

What is the current density of the solution a/m2

Mathematics
1 answer:
Jlenok [28]3 years ago
8 0

Current density of solution a/m2 is given below

Step-by-step explanation:

Current density is the measure of current generated per unit surface area of electrode.

Eg: In microbial fuel cell/fuel cells, if you are using electrode with size of 5cm x 2cm and current produced is 200mA, then current density will be,

CD= Current/(projected area of electrode)

area of rectangle= LxB= 5cm x 2cm =10cm2

CD= 200mA/10cm2

CD= 20mA/cm2

Your Current will be 200mA.

Current density will be 20mA/cm2.

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Easy question please answer :)))
Burka [1]

Answer:

Angle CED must also measure 60°. 

Because angle m is shown to be congruent to angles ABC and CDE, this means that angle m has a measure of 60 degrees.

There can only be 180 degrees in a triangle, so the measure of angle ACB must be 180-60-60, which equals 60 degrees.

Using the Vertical Angles Theorem, the measure of angle ACB is the same as the measure of angle CED.

Therefore, angle CED measures 60°.

Step-by-step explanation:

m, because Triangle ABC is similar to triangle EDC

m over 2, because Triangle ABC is congruent to triangle DCE

m + 60 degrees, because Triangle ABC is similar to triangle DCE

120 degrees − m, because Triangle ABC is congruent to triangle DCE


7 0
3 years ago
Read 2 more answers
NEED HELP ASAP 15 POINTS
NeX [460]
Use the app Socratic it helps!!
4 0
2 years ago
Place the first digit 298 / 4
torisob [31]

The answer is 74.5 ahen you divide 298÷4

8 0
3 years ago
Read 2 more answers
30 POINTS,NEED HELP ASAP !!!
zaharov [31]

Answer: OPTION A.

Step-by-step explanation:

You can observe that in the figure CDEF the vertices are:

C(-2,-1),\ D(-2,0),\ E(2,2)\ and\ F(2,1)

And in the figure C'D'E'F'  the vertices are:

C'(-8,-4),\ D'(-8,0),\ E'(8,8)\ and\ F'(8,4)

For this case, you can divide any coordinate of any vertex of the figure C'D'E'F' by any coordinate of any vertex of the figure CDEF:

For C'(-8,-4) and C(-2,-1):

\frac{-8}{-2}=4\\\\\frac{-4}{-1}=4

Let's choose another vertex. For E'(8,8) and E(2,2):

\frac{8}{2}=4\\\\\frac{8}{2}=4

You can observe that the coordinates of C' are obtained by multiplying each coordinate of C by 4 and the the coordinates of E' are also obtained by multiplying each coordinate of E by 4.

Therefore, the rule that yields the dilation of the figure CDEF centered at the origin is:

(x, y)→(4x, 4y)

7 0
3 years ago
Read 2 more answers
Pwease help me anyone. thanks :-) :-) :-) :-) :-) :-) :-) :-)!!!!
adell [148]
A)
x+3

b)
x(x+3)=340\\
x^2+3x-340=0

c)
x(x+3)=340\\ x^2+3x-340=0\\
\Delta=3^2-4\cdot1\cdot(-340)=9+1360=1369\\\sqrt{\Delta}=37\\
x_1=\dfrac{-3-37}{2}=-20\\
x_2=\dfrac{-3+37}{2}=17

It's 17.
3 0
3 years ago
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