Step-by-step explanation:
if |A|≥B then
A≥B or A≤-B
4x-10≥14 or 4x≤-14
solve 4x-10≥14
add 20 on both sides
4x≥10+14
4x≥24
divide by 4 on both ends
x≥24/4
x≥6
now solve
4x-10≤-14
add 10 on both sides
4x≤-14+10
4x≤-4
divide both sides by 4
x≤-1
(-∞,-1] U [6,∞)
Answer: 
<u>Step-by-step explanation:</u>
Since you are looking for the distance from home plate to second base, you are actually looking for the length of the diagonal of the square. Use the Pythagorean Theorem: a² + b² = c² where a and b are the side lengths and c is the length of the diagonal.
Answer:
v = 6
Step-by-step explanation:
Solve for v:
-8 (8 v + 1) - 2 = -394
-8 (8 v + 1) = -64 v - 8:
-64 v - 8 - 2 = -394
Grouping like terms, -64 v - 8 - 2 = -64 v + (-8 - 2):
-64 v + (-8 - 2) = -394
-8 - 2 = -10:
-10 - 64 v = -394
Add 10 to both sides:
(10 - 10) - 64 v = 10 - 394
10 - 10 = 0:
-64 v = 10 - 394
10 - 394 = -384:
-64 v = -384
Divide both sides of -64 v = -384 by -64:
(-64 v)/(-64) = (-384)/(-64)
(-64)/(-64) = 1:
v = (-384)/(-64)
The gcd of -384 and -64 is -64, so (-384)/(-64) = (-64×6)/(-64×1) = (-64)/(-64)×6 = 6:
Answer: v = 6
