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Gala2k [10]
3 years ago
12

What is the surface area of the figure shown? (Use 3.14 for π.)

Mathematics
2 answers:
dalvyx [7]3 years ago
5 0
The answer is c with a side of bacon hope that helps. :)

valkas [14]3 years ago
3 0
The answer is letter c hope this helps
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9x-8y=0<br> Graph the following liner equation
k0ka [10]
Y= -9x
       ---
       8

hope this helps

<span><span>
</span></span>
6 0
3 years ago
Read 2 more answers
A(n) = 1 + (n –1)(–5.7)
hammer [34]
Im guessing this is simplify so the answer would be 

<span><span>−<span>5.7n</span></span>+6.7</span><span>n
</span>__________
         n
6 0
3 years ago
M is the midpoint of AN, A has coordinates
maksim [4K]

Step-by-step explanation:

According to Question , M is the midpoint of AN, A has coordinates (-7,4), and M has coordinates (-4, -1).

<u>Figure</u><u> </u><u>:</u><u>-</u>

\setlength{\unitlength}{1 cm}\begin{picture}(20,12) \put(4,0.2){\line(0,-1){0.4}}\put(1,0){\line(1,0){6}} \put(3.8,-0.6){$\bf M(-4,-1) $} \put(1,-0.6){$\bf A (-7,4)$}   \put(6.8,-0.6){$\bf N(x,y)$} \end{picture}

Let the coordinates of N be ( x , y )

Now , according to Midpoint Formula , the midpoint of points say A(x , y) and B (x' , y') is given by ,

\boxed{\blue{ \bf Midpoint =\bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg) }}

<u>On</u><u> </u><u>using</u><u> </u><u>this</u><u> </u><u>formula</u><u> </u><u>,</u><u> </u>

=> Midpoint = \bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg)  \\ \\ => (-4, 1) = \bigg( \dfrac{x -7 }{2} , \dfrac{y + 4 }{2}\bigg) \\ \\ => -4 = \dfrac{x-7}{2} \\\\ => x - 7 = -8 \\\\ => x = 7 -8 \\\\ \boxed{\red{\sf=> x = -1 }} \\\\ => \dfrac{y+4}{2}=-1 \\\\=> y +4 = -2 \\ \\ y = -4-2 \\\\\boxed{\red{\sf=> y = -6 }}

8 0
3 years ago
Read 2 more answers
Find the area of the trapezoid.<br> b1=5<br> b2=7<br> h=4<br><br> PLEASE EXPLAIN TOO!
olga_2 [115]

Step-by-step explanation:

The formula for finding the area of a trapezoid is\frac{b_{1} + b_{2} }{2} ×h

Start by substituting the values given in the problem into the formula

\frac{5+7}{2} ×4

Now Simply/solve

\frac{12}{2} ×4

6×4

24

The area of the trapezoid is 24units^{2}

I hope this helps!!!

4 0
3 years ago
Read 2 more answers
Please help! Consider the given circle with the shaded sector xy and central angle 225. The circumference is 30 units
OleMash [197]

\textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ C=30\pi \end{cases}\implies 30\pi =2\pi r\implies \cfrac{30\pi }{2\pi }=r\implies \boxed{15=r} \\\\[-0.35em] ~\dotfill

\textit{arc's length}\\\\ s = \cfrac{\theta \pi r}{180}~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ r=15\\ \theta =225 \end{cases}\implies \widehat{XY}=\cfrac{(225)\pi (15)}{180}\implies \boxed{\widehat{XY}\approx 58.90} \\\\[-0.35em] ~\dotfill\\\\ \textit{area of a circle}\\\\ A=\pi r^2\qquad \qquad A=\pi (15)^2\implies A=225\pi \implies \boxed{A\approx 706.86}

6 0
3 years ago
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