Factor each expression

Mathematics

2 answers:

disa [49]2 years ago

7 0

What does that mean???

const2013 [10]2 years ago

3 0

Please post a picture of these expressions or list them?

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During a radio contest, $50 is added to the prize money each time a caller answers the contest question incorrectly. the first c

omeli [17]

Answer:

50x+100=y
y=550

Step-by-step explanation:

Since the first caller can win $100, you add 100 onto the end. After you add 50 for every person who answered incorrectly. X being amount tried/answered incorrectly, and Y being the amount you can win at that given time

6 0

2 years ago

Find the value of d.

Ket [755]

First find the value or (DEA)
For this you will have to use the Pythagorean theory,
${a}^{2} + {b}^{2} = {c}^{2}$
C is mainly the hypotenuse,
Meaning you either want to find A or B,

Since the hypotenuse has two segments, both values are 10, then just add them together making it 20,

Then 16 will be A or B, in this case it will be A,

To find a you must first move A to the other side by doing the opposite,
${b}^{2} = {c}^{2} - {a}^{2}$
Now plug in the values,
${b}^{2} = {20}^{2} - {16}^{2}$
${b}^{2} = 400 - 256$
${b}^{2} = 144$
Now just find the square root of both factors,
$\sqrt{ {b}^{2} } = \sqrt{12}$
The value of (DEA) is,
$b = 12$
Now we want to find (d)
Since 12 is the value of the base, then divide it 2 to find (DE), after just repeat the whole process but with the value of hypotenuse 10 instead of 20 since we want to find the smaller triangle,
${a}^{2} = {c}^{2} - {b}^{2}$
Now plug in the value
${a}^{2} = {10}^{2} - {6}^{2}$
${a}^{2} = 100 - 36$
${a}^{2} = 64$
Now find the square root of both factors,
$\sqrt{ {a}^{2} } = \sqrt{64}$
$a = 8$

The value of (d) is (8)

Hope this helped
:D

4 0

2 years ago

What is the name of the place value of 9 in 199

Sliva [168]

The name of place value of 9 in 199 is ones.

The second 9 has a value of tens.

The number 1 has a place value of hundreds.

8 0

3 years ago

Read 2 more answers

Write the given polynomial in standard form and write its degree .

olga nikolaevna [1]