Answer:
1 - C
2 - A
3 - D
4 - B
Step-by-step explanation:
Consider an arbitrary function y=f(x).
1. f(x)>0 means y>0. y>0 determines all points on the graph which have positive y-coordinates. Positive y are corresponding to those x from the domain, for which graph lies above the x-axis. So 1 - C
2. f(x)<0 means y<0. y<0 determines all points on the graph which have negative y-coordinates. Negative y are corresponding to those x from the domain, for which graph lies below the x-axis. So 2 - A
3. To find y-intercept, we have to substitute x=0, so input is zero. Hence, 3 - D
4. To find x-intercept, we have to substitute y=0, so output is 0. Hence, 4 - B
Hello, here is the answer!
Answer: 375
Step-by-step explanation: 7+8=15
15x25=375
375 paper clips
Slope is vertical change over horizontal change. Since coordinates conveniently give both the horizontal and vertical coordinates of a points, we can use the coordinates of both points to differentiate, or find the change horizontally and the change vertically between the two points.
2x+3x+4 is equivalent with 5x+4 and 3(4x+2) is equivalent to 12x+6 and then the last two
Answer:
0.362
Step-by-step explanation:
When drawing randomly from the 1st and 2nd urn, 4 case scenarios may happen:
- Red ball is drawn from the 1st urn with a probability of 9/10, red ball is drawn from the 2st urn with a probability of 1/6. The probability of this case to happen is (9/10)*(1/6) = 9/60 = 3/20 or 0.15. The probability that a ball drawn randomly from the third urn is blue given this scenario is (1 blue + 5 blue)/(8 red + 1 blue + 5 blue) = 6/14 = 3/7.
- Red ball is drawn from the 1st urn with a probability of 9/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (9/10)*(5/6) = 45/60 = 3/4 or 0.75. The probability that a ball drawn randomly from the third urn is blue given this scenario is (1 blue + 4 blue)/(8 red + 1 blue + 1 red + 4 blue) = 5/14
- Blue ball is drawn from the 1st urn with a probability of 1/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (1/10)*(5/6) = 5/60 = 1/12. The probability that a ball drawn randomly from the third urn is blue given this scenario is (4 blue)/(9 red + 1 red + 4 blue) = 4/14 = 2/7
- Blue ball is drawn from the 1st urn with a probability of 1/10, red ball is drawn from the 2st urn with a probability of 1/6. The probability of this event to happen is (1/10)*(1/6) = 1/60. The probability that a ball drawn randomly from the third urn is blue given this scenario is (5 blue)/(9 red + 5 blue) = 5/14.
Overall, the total probability that a ball drawn randomly from the third urn is blue is the sum of product of each scenario to happen with their respective given probability
P = 0.15(3/7) + 0.75(5/14) + (1/12)*(2/7) + (1/60)*(5/14) = 0.362
