3 years ago

Answer this plz u can just put the number like that and put the color next to it plz and thank u I will give u all my points

Mathematics

2 answers:

Darya [45]3 years ago

5 0

Answer: what is the question?

nasty-shy [4]3 years ago

5 0

24 because if you add 11 and 49 and 38 then minus 39 it’s 24

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Construct the indicated confidence interval for the difference between the two population means. Assume that the two samples are

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Answer:

The indicated confidence interval for the difference between the two population means is (-1.5159, 7.5159)

Step-by-step explanation:

Let the drying times of type A be the first population and the drying times of type B be the second population. Then

We have small sample sizes $n_{1} = 11$ and $n_{2} = 9$ , besides $\bar{x}_{1} = 71.5$ , $s_{1} = 3.4$ , $\bar{x}_{2} = 68.5$ and $s_{2} = 3.6$ . Therefore, the pooled

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$s_{p}^{2} = \frac{(n_{1}-1)s_{1}^{2}+(n_{2}-1)s_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(11-1)(3.4)^{2}+(9-1)(3.6)^{2}}{11+9-2} = 12.1822$

The 99% confidence interval for the true mean difference between the mean drying time of type A and the mean drying time of type B is given by

$(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.01/2}s_{p}\sqrt{\frac{1}{11}+\frac{1}{9}}$ , i.e.,

$(71.5-68.5)\pm t_{0.005}(3.4903)\sqrt{\frac{1}{11}+\frac{1}{9}}$

where $t_{0.005}$ is the 0.5th quantile of the t distribution with (11+9-2) = 18 degrees of freedom. So

$3\pm(-2.8784)(3.4903)(0.4495)$ , i.e.,

the indicated confidence interval for the difference between the two population means is (-1.5159, 7.5159)

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