Answer:
Molecular formula = C₁₂H₁₂O₄
Empirical formula is C₃H₃O.
Explanation:
Given data:
Mass of C = 91.63 g
Mass of H = 7.69 g
Mass pf O = 40.81 g
Molar mass of compound = 220 g/mol
Empirical formula = ?
Molecular formula = ?
Solution:
Number of gram atoms of H = 7.69 / 1.01 = 7.61
Number of gram atoms of O = 40.81 / 16 = 2.55
Number of gram atoms of C = 91.63 / 12 = 7.64
Atomic ratio:
C : H : O
7.64/2.55 : 7.61 /2.55 : 2.55/2.55
3 : 3 : 1
C : H : O = 3 : 3 : 1
Empirical formula is C₃H₃O.
Molecular formula:
Molecular formula = n (empirical formula)
n = molar mass of compound / empirical formula mass
Empirical formula mass = 3×12+ 3×1.01 +16 = 55.03
n = 220 / 55.03
n = 4
Molecular formula = 4 (empirical formula)
Molecular formula = 4 (C₃H₃O)
Molecular formula = C₁₂H₁₂O₄
Because it is a covalent bond meaning that they share the electrons to achieve full valence.
the physical properties of ammonium sulphate are colorless gas, less dense than air, pungent shell, very soluble in water, alkaline gas
Answer:
1.54grams
Explanation:
Molarity of a solution = n/V
Where;
n = number of moles (mol)
V = volume (L)
Based on the information given in this question;
Volume of NaOH solution = 5.0 × 10ml
= 50ml = 50/1000 = 0.050 L
Molarity = 0. 77 M
Using; Molarity = n/V
0.77 = n/0.05
n = 0.77 × 0.05
n = 0.0385mol
To find the mass (grams) of NaOH in the solution, we use the following formula:
mole (n) = mass/molar mass
Molar mass of NaOH = 23 + 1 + 16 = 40g/mol
0.0385 = mass/40
mass = 0.0385 × 40
mass = 1.54grams.
