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Dafna1 [17]
3 years ago
8

WILL MARK BRAINLIEST!!! Think about how to determine the molar mass of NH4OH,

Chemistry
1 answer:
Andrej [43]3 years ago
3 0
The molar mass of NH4OH is 35
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The density of aluminum is 2.7 g/mL if I add a piece of aluminum to a graduated cylinder of water in the water level increases b
viva [34]
The answer would be 5.5g because you have to subtract 8.2 minus 2.7 and you get 5.5g so basically the answer is C.
8 0
3 years ago
What effect does the anion of an ionic compound have on the appearance of the solution?
choli [55]

Answer: B. The anion affects the color of the solution more than the intensity of the color.

Explanation:

An ionic bond is gotten when an electron is transferred from a metal atom to a non-metal one. It should be noted that the ionic bonds simply has an anion and a cation.

An anion is formed when a valence election is gained by a non metal while a cation is formed when the metal ion misplaces a valence electron.

The effect of the anion of an ionic compound on the appearance of the solution is that the anion affects the color of the solution more than the intensity of the color.

6 0
3 years ago
The reaction 2KBr(s) →+ Br2(l) + 2K(s) is a <br>Decomposition reaction
klasskru [66]
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5 0
3 years ago
Ignore the answer I have selected but please help!! Ty in advance, also please explain
weeeeeb [17]

Answer:

Iodine is most reactive because it is very close to having a "full shell" which is 8 electrons so they are "eager" to gain the last electron to became balanced, so that makes it the most reactive. Hope that helps:)

Explanation:

4 0
3 years ago
A piston chamber filled with ideal gas is kept in a constant-temperature bath at 25.0°C. The piston expands from 25.0 mL to 75.0
larisa [96]

Answer : The work done by the system is, 2.2722 J

Explanation :

The expression used for work done in reversible isothermal expansion will be,

w=nRT\ln (\frac{V_2}{V_1})

where,

w = work done = ?

n = number of moles of gas  = 0.00100 mole

R = gas constant = 8.314 J/mole K

T = temperature of gas  = 25^oC=273+25=298K

V_1 = initial volume of gas  = 25 mL

V_2 = final volume of gas  = 75 mL

Now put all the given values in the above formula, we get:

w=0.00100mole\times 8.314J/moleK\times 298K\times \ln (\frac{75}{25})

w=2.722J

Therefore, the work done by the system is, 2.2722 J

8 0
3 years ago
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