Answer:
The right word to fill the blank space is GREATER THAN.
Explanation:
In nature, heat in form of temperature is usually transfer from the region of higher temperature to the region of lower temperature. Thus, for heat to be transfer from one substance to another one, the temperature will flow from the body with the higher temperature to that which has a lower temperature, the substance that is giving out the heat must have a higher temperature.
Answer: 
.
Explanation:
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
(1)
![S_{monoclinic}+O_2(g)\rightarrow SO_2(g)/tex] [tex]\Delta H^0_2=-296.36kJ](https://tex.z-dn.net/?f=S_%7Bmonoclinic%7D%2BO_2%28g%29%5Crightarrow%20SO_2%28g%29%2Ftex%5D%20%5Btex%5D%5CDelta%20H%5E0_2%3D-296.36kJ)
(2)
The final reaction is:
(3)
By subtracting (1) and (2)
Hence the enthalpy change for the transformation S(rhombic) → S(monoclinic) is 0.3kJ
The minimum mass of Zinc, Zn that needs to be added to 0.500 g of iodine so that the iodine fully reacts is 0.128 g
<h3>Balanced equation </h3>
Zn + I₂ —> ZnI₂
Molar mass of Zn = 65 g/mol
Mass of Zn from the balanced equation = 1 × 65 = 65 g
Molar mass of I₂ = 127 × 2 = 254 g/mol
Mass of I₂ from the balanced equation = 1 254 = 254 g
SUMMARY
From the balanced equation above,
254 g of I₂ required 65 g of Zn
<h3>How to determine the mass of Zn needed </h3>
From the balanced equation above,
254 g of I₂ required 65 g of Zn
Therefore,
0.5 g of I₂ will require = (0.5 × 65) / 254 = 0.128 g of Zn
Thus, the minimum mass of Zn required is 0.128 g
Learn more about stoichiometry:
brainly.com/question/14735801
Answer:
mNaNO3 =765g
Explanation:
First, we write the balanced chemical equation representing the chemical reaction that happened between aluminum nitrate and sodium chloride.
Balanced chemical equation:
AL(NO3)3+3NaCl ⟶ 3 NaNO3+AlCl3
According to the equation, each mole of aluminum nitrate requires three moles of sodium chloride. Thus, the required number of moles of sodium chloride is
4 Mol ⋅ 3 = 12mol
Based on the data provided in the table, there were 9 moles of sodium chloride used in the reaction, which was not enough for the entirety of aluminum nitrate to react. So, sodium chloride must have been the limiting reactant.
Therefore, we use the number of moles (n) of sodium chloride to calculate the number of moles of sodium nitrate, which has a 1:1 ratio with sodium chloride.
Number of moles sodium nitrate:
nNaNO3=nNaCl
nNaNO3 = 9 mol
We can also calculate the mass (m) of sodium nitrate that was produced by multiplying its number of moles by its molar mass (MM), 85.00g/mol.
Mass of sodium nitrate produced:
mNaNO3 = nNaNO3 ⋅ MMNaNO3
mNaNO3 = 9 mol ⋅ 85.00 g/mol
mNaNO3 =765g
