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murzikaleks [220]
3 years ago
11

2. An electric heating element is connected to a 110 V circuit and a current of 3.2 A is flowing though the element. How much en

ergy is used up during a period of 5 hours by the elemets? A. 550 Wh B. 2,580 Wh C. 352 Wh D. 1,760 Wh
Chemistry
2 answers:
Kisachek [45]3 years ago
7 0

Answer:

i believe it is D as well

Explanation:

ehidna [41]3 years ago
3 0
I think its D 1,760Wh

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Based on the equations below, which metal is the most active? pb(no3)2 (aq) + ni (s) â ni(no3)2 (aq) + pb (s) pb(no3)2 (aq) + ag
erastova [34]

Answer is: nickel (Ni) is the most active metal.

Chemical reaction 1: Pb(NO₃)₂(aq) + Ni(s) → Ni(NO₃)₂(aq) + Pb(s).

Chemical reaction 2: Pb(NO₃)₂(aq) + Ag(s) → no reaction.

Chemical reaction 3: Cu(NO₃)₂(aq)) + Ni(s) → Ni(NO₃)₂(aq) + Cu(s).

From chemical reactions 1 and 3, we can conclude that nickel is more reactive than lead (Pb) and copper (Cu), because lead is more reactive than silver (Ag), chemical reaction 2, nickel is also more reactive than silver.

In chemical reaction 2, no reaction occurs because silver is less reactive than lead. Lead is higher in activity series of metals and can not be reduced.

Nickel is higher in activity series of metals than lead, copper and silver.

The activity series is a series of metals from highest to lowest reactivity. Metal higher in the reactivity series will displace another.

3 0
3 years ago
What is an example of a neutral ion.
VARVARA [1.3K]
A neural sodium ion.
4 0
3 years ago
If the percent transmittance is is 64.9 in 0.2M standard CuSO4, what is the absorption?
Natali [406]
Explain it a little more ?
5 0
3 years ago
It takes 338. kJ/mom to break a carbon-chlorine single bond. Calculate the maximum wavelength of light for which a carbon-chlori
Vesnalui [34]

Answer: The maximum wavelength of light for which a carbon-chlorine Single bond could be broken by absorbing a single photon is 354 nm

Explanation:

The relation between energy and wavelength of light is given by Planck's equation, which is:

E=\frac{Nhc}{\lambda}

where,

E = energy of the light  = 338kJ=338000J    (1kJ=1000J)

N= avogadro's number

h = Planck's constant

c = speed of light

\lambda = wavelength of light

338\times 1000J=\frac{6.023\times 10^{23}\times 6.6\times 10^{-34}\times 3\times 10^{8}}{\lambda}    

{\lambda}=0.354\times 10^{-6}m=354nm     (1nm=10^{-9}m

Thus the maximum wavelength is 354 nm

6 0
3 years ago
What mass of ammonia can be produced if 13.4 grams of nitrogen gas reacted ?
aivan3 [116]

Answer:

If 13.4 grams of nitrogen gas reacts we'll produce 16.3 grams of ammonia

Explanation:

Step 1: Data given

Mass of nitrogen gas (N2) = 13.4 grams

Molar mass of N2 = 28 g/mol

Molar mass of NH3 = 17.03 g/mol

Step 2: The balanced equation

N2 + 3H2 → 2NH3

Step 3: Calculate moles of N2

Moles N2 = Mass N2 / molar mass N2

Moles N2 = 13.4 grams / 28.00 g/mol

Moles N2 = 0.479 moles

Step 4: Calculate moles of NH3

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

For 0.479 moles N2 we'll produce 2*0.479 = 0.958 moles

Step 5: Calculate mass of NH3

Mass of NH3 = moles NH3 * molar mass NH3

Mass NH3 = 0.958 moles * 17.03 g/mol

Mass NH3 = 16.3 grams

If 13.4 grams of nitrogen gas reacts we'll produce 16.3 grams of ammonia

3 0
3 years ago
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