<h3>
Answer: Choice A</h3>
- Domain: x > 4
- Range: y > 0
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Explanation:
We want to avoid having a negative number under the square root. Solving
leads to 
So it appears the domain could involve x = 4 itself; however, if we tried that x value, then we'd get a division by zero error.
So in reality, the domain is x > 4.
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The range of y = sqrt(x) is the set of positive real numbers. So y > 0 is the range for this equation. Shifting left and right does not affect the range, so the range of y = sqrt(x-4) is also y > 0.
We are dividing a positive number (3) over some positive number in the denominator. Overall, the expression
is positive because positive/positive = positive.
Therefore, the range of the given equation is y > 0
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The graph is shown below. We have a vertical asymptote at x = 4 and a horizontal asymptote at y = 0. The green curve is fenced in the upper right corner (northeast corner).
Answer:
n = 6
Step-by-step explanation:
2 = 
multiply both sides by 3
=> n = 6
Answer:
B or the third option you put.
Step-by-step explanation:
PEMDAS tells us to use multiplication and division before addition and subtraction.
<u>-5(8) </u>÷ 10 - <u>14 ÷ 7</u> - <u>(-2)(3)</u>
<u> -40 ÷ 10</u> - 2 - -6
<u>-4 - 2 </u> + 6 <em>two negatives make a positive so - - 6 = + 6</em>
<u> -6 +6</u>
0
Answer: 0