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Andrew [12]
2 years ago
11

Write 14.236 as a fraction

Mathematics
2 answers:
geniusboy [140]2 years ago
5 0

Answer:                                                    59

it would be 3559 over 225 or also 14 ___

                                                                  250

Step-by-step explanation:

srry its messy

Maru [420]2 years ago
4 0
First you put 14.236 over 1, then times it by 1000/1000. And you get 14236/1000. Then you divide 14236/1000 by 4 and get 3559/250. So that makes your answer 14 59/250.
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3 years ago
The measure of one angle of a right triangle is 56∘ more than the measure of the smallest angle. Find the measure of the smalles
GrogVix [38]

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7 0
2 years ago
Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution. At Meadowbrook Hospital, the mean we
Marina86 [1]

Answer:

Required Probability = 0.1283 .

Step-by-step explanation:

We are given that at Meadow brook Hospital, the mean weight of babies born to full-term pregnancies is 7 lbs with a standard deviation of 14 oz.

Firstly, standard deviation in lbs = 14 ÷ 16 = 0.875 lbs.

Also, Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution.

Let X = mean weight of the babies, so X ~ N(\mu = 7 lbs , \sigma^{2}  = 0.875^{2}  lbs)

The standard normal z distribution is given by;

              Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, X bar = sample mean weight

             n = sample size = 4

Now, probability that the average weight of the four babies will be more than 7.5 lbs = P(X bar > 7.5 lbs)

P(X bar > 7.5) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{7.5-7}{\frac{0.875}{\sqrt{4} } }  ) = P(Z > 1.1428) = 0.1283 (using z% table)

Therefore, the probability that the average weight of the four babies will be more than 7.5 lbs is 0.1283 .

8 0
3 years ago
HELP PLEASE!<br>nvm lololololoololl
antoniya [11.8K]

Answer:

I can't help you, it doesn't indicate what you need

6 0
2 years ago
Read 2 more answers
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