The first thing to do is find the rectangular warehouse area.
We have then:
A = (12) * (18) = 216
A = 216 m ^ 2
We now look for the area of each acoustic tile square:
A '= (1) ^ 2 = 1
A '= 1 m ^ 2
We look for acoustic tile squares number:
N = (A) / (A ')
N = (216) / (1)
N = 216
Finally we look for the total weight:
W = (1/4) * (216)
W = 54 Kg
Answer:
The total weight of the tile required to cover the ceiling is:
W = 54 Kg
Answer:
2.5
Step-by-step explanation:
0.067 is the answer for this
Try to use Socratic or Photomath
There are 1600 metres in 1 mile, so 10095÷1600= 6.3 miles/s
