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3 years ago

Sorry here's another problem I need help with

Mathematics

1 answer:

tiny-mole [99]3 years ago

5 0

Answer:

Step-by-step explanation:

You need to work backwards to solve this equation!

9 - 17 = -8

w / -4 = -8

32 / -4 = -8

Which means that w = 32

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On moving day, Jorge needs to rent a truck. The length of the cargo space is 12 ft, and the height is 1 ft less than the width.

lidiya [134]

Answer:

12ft $\times$ 7ft $\times$ 6ft

Step-by-step explanation:

Given that truck can hold = 504 $ft^{3}$ i.e.

Volume, V = 504 $ft^{3}$

Length of cargo space = 12 ft

Let width of cargo space = w ft

As per question statement:

Let height of cargo space = (w-1) ft

To find: The Dimensions of Cargo Space

Formula for Volume of Cargo Space:

V = Length $\times$ Width $\times$ Height

Putting the given values and conditions:

504 = 12 $\times$ $w \times (w-1)$

$\Rightarrow w(w-1) = \dfrac{504}{12}\\\Rightarrow w^{2} -w = 42\\\Rightarrow w^{2} -w - 42=0\\\Rightarrow w^{2} -7w +6w -42 =0\\\Rightarrow w(w -7) +6(w -7) =0\\\Rightarrow (w -7)(w+6) = 0\\\Rightarrow w =7, -6$

Dimensions can not be negative, so width, w = 7 ft

Height = (w-1) = 7-1 = 6 ft

So, the dimensions are 12ft $\times$ 7ft $\times$ 6ft.

5 0

3 years ago

Will Mark Brainliest !!

NeX [460]

Answer:

y=2/5 - 1/5

explanation:

6 0

3 years ago

4. Find the geometric mean of 4 and 12. 24 8

r-ruslan [8.4K]

The geometric mean of two numbers is the square root of their product.

sqrt{4 • 12}

sqrt{48}

sqrt{16} •sqrt{3}

4•sqrt{3}.

The geometric mean of 4 and 12 is

4•sqrt{3}.

5 0

3 years ago

A hackberry tree has roots that reach a depth of

Degger [83]

Answer:

24.6967 meters

Step-by-step explanation:

The roots of the tree go 6 and 5 over 12 meters below the ground level.

Now, 6 and 5 over 12 meters is equivalent to 6.4167 meters.

Again the top of the tree is 18.28 meters high from the ground level.

Therefore, the total height of the tree from the bottom of the root to the top is

(6.4167 +18.28) = 24.6967 meters (Answer)

5 0

3 years ago

Find f. A) 7.4 B) 8.2 C) 10.5 D) 11.1

tatyana61 [14]

F=72

g=6

------------

$\cos { \left( F \right) } =\frac { { e }^{ 2 }+{ g }^{ 2 }-{ f }^{ 2 } }{ 2eg }$

Therefore:

$\cos { \left( 72 \right) } =\frac { { e }^{ 2 }+{ 6 }^{ 2 }-{ f }^{ 2 } }{ 2\cdot e\cdot 6 } \\ \\ \cos { \left( 72 \right) } =\frac { { e }^{ 2 }+36-{ f }^{ 2 } }{ 12e }$

$\\ \\ 12e\cdot \cos { \left( 72 \right) } ={ e }^{ 2 }+36-{ f }^{ 2 }\\ \\ \therefore \quad { f }^{ 2 }={ e }^{ 2 }-12e\cdot \cos { \left( 72 \right) } +36\\ \\ \therefore \quad f=\sqrt { { e }^{ 2 }-12e\cdot \cos { \left( 72 \right) +36 } } \\ \\ \therefore \quad f=\sqrt { e\left( e-12\cos { \left( 72 \right) } \right) +36 }$

But what is e?

E=76

G=32

g=6

And:

$\frac { e }{ \sin { \left( E \right) } } =\frac { g }{ \sin { \left( G \right) } }$

Which means that:

$\frac { e }{ \sin { \left( 76 \right) } } =\frac { 6 }{ \sin { \left( 32 \right) } } \\ \\ \therefore \quad e=\frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } }$

If you take this value into account, you will discover that f is...

$f=\sqrt { \frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } } \left( \frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } } -12\cos { \left( 72 \right) } \right) +36 } \\ \\ \therefore \quad f=10.8\quad \left( 1\quad d.p \right)$

So I would have to say that the answer is approximately (c).

6 0

3 years ago

Sorry here's another problem I need help with​

Sorry here's another problem I need help with