Answer:
11 nickels, 15 dimes, 22 quarters
Step-by-step explanation:
number of nickels = x
number of dimes = x+4
number of quarters = 2x
- - - - - -
total of nickels = 5x cents
total of dimes = 10x + 40 cents
total of quarters = 50x cents
- - - - - -
755 = 5x + 10x + 40 + 50x
755 = 65x + 40
715 = 65x
x = 11
x+4 = 15
2x = 22
<span>(x – 13)(x + 8) = 196
</span>x * x + x * 8 - 13 * x - 13 * 8 = 196
x² + 8x - 13x - 104 = 196
x² - 5x - 104 - 196 = 0
x² - 5x - 300 = 0
The missing side length is 28
A + C
(-5, -7) is 7 units to the left of point H
(-7, 7) is more than 7 units up and left of point H
the x axis is at (infinity, 0), being only 7 points up from point H
Answer:
C) ![x^{27} (\sqrt[3]{y} )](https://tex.z-dn.net/?f=x%5E%7B27%7D%20%28%5Csqrt%5B3%5D%7By%7D%20%29)
Step-by-step explanation:
a) if the two gloves someone receives might both be for the left hand or right hand.
b) if each sister gets one left and one right.
Soln:
a) So i thought about dissectng the problem first into finding the number of ways in which I could make pairs of gloves:
C(12, 2)
then I asked how many ways could the sets of gloves be assigned amongst the 6 sisters:
<span><span>6!</span><span>6!</span></span>
and taking the product of this would give me the amount of ways this could occur:
= C(12,2) * 6!
then for part b)
using this same idea except:
C(6,1) C(6,1) for the left and right glove each .
the C(6,1)*C(6,1)*6!
Right way to think them through?
