Just do how many minutes are in a hour and do that for 2days but 24 times two
You have to multiply the 6 by both s and -9
So you will get 6s - 54 which is the answer
Answer:
The concept which best describes the change of the population is the derivative of 
.
Step-by-step explanation:
Observe that the function describes the amount of rabbits at the time t (in years) but no the rate of change of the population at a given instant. So you have to use the derivative of 
to obtain that rate of change at any instant. For example, if we derivate the function we obtain:
And if we want to find the rate of change at 
years we evaluate
rabbits/year
Answer:
There is nothing here!
Step-by-step explanation:
I don't see anything to solve.
: )
<span>Dawn was at 6 am.
Variables
a = distance from a to passing point
b = distance from b to passing point
c = speed of hiker 1
d = speed of hiker 2
x = number of hours prior to noon when dawn is
The first hiker travels for x hours to cover distance a, and the 2nd hiker then takes 9 hours to cover that same distance. This can be expressed as
a = cx = 9d
cx = 9d
x = 9d/c
The second hiker travels for x hours to cover distance b, and the 1st hiker then takes 4 hours to cover than same distance. Expressed as
b = dx = 4c
dx = 4c
x = 4c/d
We now have two expressions for x, set them equal to each other.
9d/c = 4c/d
Multiply both sides by d
9d^2/c = 4c
Divide both sides by c
9d^2/c^2 = 4
Interesting... Both sides are exact squares. Take the square root of both sides
3d/c = 2
d/c = 2/3
We now know the ratio of the speeds of the two hikers. Let's see what X is now.
x = 9d/c = 9*2/3 = 18/3 = 6
x = 4c/d = 4*3/2 = 12/2 = 6
Both expressions for x, claim x to be 6 hours. And 6 hours prior to noon is 6am.
We don't know the actual speeds of the two hikers, nor how far they actually walked. But we do know their relative speeds. And that's enough to figure out when dawn was.</span>
