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liubo4ka [24]
3 years ago
10

Can someone help me please

Mathematics
1 answer:
yuradex [85]3 years ago
4 0
I don't know what to do
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Suppose the equation ax^2+bx+c=0 has no real solution and a graph of the related function has a vertex that lies in the second q
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If it has no real solutions, that means the graph does not intersect the x axis

since we have ax^2+bx+c=0, the parabola opens either up or down
since the vertex is in the second quadrant (x is negative and y is positive in this reigon) and the graph does not cross the x axis, the parabola must open up
if the value of 'a' is positive, then the parabola opens up

so 'a' must be positive



if it is translated to the 4th quadrant, then the vertex is now below the x axis
it will now have 2 x intercepts because the vertex is in the 4th quadrant and look at a graph of a parabola opening up with vertex in 4th quadrant and seehow many time it crosses the x axis
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Como divido numeros radicales?​
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Do you have a specific question or like nd question example with numbers

¿Tiene una pregunta específica o como ejemplo de pregunta con números?

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3 years ago
Is 62.90 bigger or 62.09?
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62.90

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To compare decimal, try to say the decimal with its place value, and its way easier to compare.

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Read 2 more answers
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