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Harrizon [31]
4 years ago
8

Out of 200 bulbs in a box, 12 bulbs are defective. One bulb is taken out at random from the box. What is the probability that th

e drawn bulb is not defective?
Mathematics
1 answer:
Lunna [17]4 years ago
4 0
12 out of 200 is 6% so the chance of you getting a working bulb is 94%,
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Which choice is equivalent to(√6)( √8). How do you solve
beks73 [17]

Answer:

B

Step-by-step explanation:

(6)^1/2 × (8)^1/2

6^1/2 × 2 (2)^1/2

4 (3)^1/2

7 0
3 years ago
Can i please get help on this Question?
Shalnov [3]
Hi there!

Given:
4m +  \frac{23 + n}{p - 3}  \\ m = 7 \\ n = 2 \\ p = 8

In order to evaluate the expression with the given values of m, n and p, we must substitute then into the expression. Then we use the correct order of operations (PEMDAS) to calculate.

Let's substitute first!
4(7)  +  \frac{(23 + 2)}{(8 - 3)}

Now find the numerator and denominator of the fraction.
4(7) +  \frac{25}{5}

Next up: multiplying
28 +  \frac{25}{5}

Divide the fraction.
28 + 5

And finally add the integers.
33

Hence, the answer is 33.
~ Hope this helps you!
3 0
3 years ago
Read 2 more answers
If the point (2-3) lies on the graph of the equation 2y=ax-7 then find the value of a <br>​
11111nata11111 [884]

Answer:

\frac{1}{2}

Step-by-step explanation:

if to substitute the coordinates of the point into the equation:

2*(-3)=2*a-7, then a=1/2

5 0
3 years ago
the half-life of strontium-90 is approximately 29 years. how much of a 500 g sample of strontium-90 will remain after 58 years​
Yuliya22 [10]

Answer:  125 g

<u>Step-by-step explanation:</u>

A = P_o\cdot e^{kt}\\\\\text{First, use the given information to find k:}\\\\\bullet A=\dfrac{1}{2}P_o\\\\\bullet k = unknown\\\\\bullet t=29\text{ years}\\\\\dfrac{1}{2}P_o=P_o\cdot e^{k(29)}\\\\\\\dfrac{1}{2}=e^{k(29)}\qquad divided\ both\ sides\ by\ P_o\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=ln\bigg(e^{k(29)}\bigg)\qquad applied\ ln\ to\ both\ sides\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=29k\qquad simplified-ln\ and\ e\ cancel\ out\\\\\\\dfrac{ln\bigg(\dfrac{1}{2}\bigg)}{29}=k\qquad divided\ 29\ from\ both\ sides\\\\\\-0.0239=k

\text{Now, use the following in the equation to solve for A:}\\\\\bullet A=unknown\\\bullet P_o=500\\\bullet k=-0.0239\\\bullet t=58\text{ years}\\\\A=500\cdot e^{(-0.0239)(58)}\\\\.\quad=500\cdot e^{-1.386}\\\\.\quad=125

8 0
4 years ago
Alicia received the following seven scores on her math assignments.
tresset_1 [31]
The median is your answer. Hope this helps.
7 0
4 years ago
Read 2 more answers
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