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murzikaleks [220]

4 years ago

15

ASAP HELP PLEASE!!!!!!!!!!!!

1 answer:

tensa zangetsu [6.8K]4 years ago

8 0

The answer is 170 minutes or 68/24 hours so, common denominator is 1/24 hours.
1) 1+3/4+2/3+1/4+1/6=(24+18+16+6+4)/24 so it is 68/24 and times 60 it will be 170.

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Identify p, b, and a. Do not solve for the unknown.<br><br> 10.9 is what percent of 34?

Rashid [163]

10.9 = x% of 34

10.9 is the amount
x% is the percent
34 is the base

8 0

3 years ago

A biker travels 10 miles in two hours, what is his speed?

Alinara [238K]

Answer:

5 mph

Step-by-step explanation:

10/2 is 5 miles in one hour.

7 0

3 years ago

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4.) What is the exact value of sinθ when θ lies in Quadrant II and cosθ=−513

dimaraw [331]

Answer:

Part 4) $sin(\theta)=\frac{12}{13}$

Part 10) The angle of elevation is $40.36\°$

Part 11) The angle of depression is $78.61\°$

Part 12) $arcsin(0.5)=30\°$ or $arcsin(0.5)=150\°$

Part 13) $-45\°$ or $225\°$

Step-by-step explanation:

Part 4) we have that

$cos(\theta)=-\frac{5}{13}$

The angle theta lies in Quadrant II

so

The sine of angle theta is positive

Remember that

$sin^{2}(\theta)+ cos^{2}(\theta)=1$

substitute the given value

$sin^{2}(\theta)+(-\frac{5}{13})^{2}=1$

$sin^{2}(\theta)+(\frac{25}{169})=1$

$sin^{2}(\theta)=1-(\frac{25}{169})$

$sin^{2}(\theta)=(\frac{144}{169})$

$sin(\theta)=\frac{12}{13}$

Part 10)

Let

$\theta$ ----> angle of elevation

we know that

$tan(\theta)=\frac{85}{100}$ ----> opposite side angle theta divided by adjacent side angle theta

$\theta=arctan(\frac{85}{100})=40.36\°$

Part 11)

Let

$\theta$ ----> angle of depression

we know that

$sin(\theta)=\frac{5,389-2,405}{3,044}$ ----> opposite side angle theta divided by hypotenuse

$sin(\theta)=\frac{2,984}{3,044}$

$\theta=arcsin(\frac{2,984}{3,044})=78.61\°$

Part 12) What is the exact value of arcsin(0.5)?

Remember that

$sin(30\°)=0.5$

therefore

$arcsin(0.5)$ -----> has two solutions

$arcsin(0.5)=30\°$ ----> I Quadrant

or

$arcsin(0.5)=180\°-30\°=150\°$ ----> II Quadrant

Part 13) What is the exact value of $arcsin(-\frac{\sqrt{2}}{2})$

The sine is negative

so

The angle lies in Quadrant III or Quadrant IV

Remember that

$sin(45\°)=\frac{\sqrt{2}}{2}$

therefore

$arcsin(-\frac{\sqrt{2}}{2})$ ----> has two solutions

$arcsin(-\frac{\sqrt{2}}{2})=-45\°$ ----> IV Quadrant

or

$arcsin(-\frac{\sqrt{2}}{2})=180\°+45\°=225\°$ ----> III Quadrant

5 0

3 years ago

2.2 geometry i need the answers

Strike441 [17]

Answer:

Where’s the picture

Step-by-step explanation:

8 0

3 years ago

Wangari plants trees at a constant rate of 1212 trees every 33 hours. Write an equation that relates pp, the number of trees Wan

igor_vitrenko [27]

Answer:

$p=4h$

Step-by-step explanation:

Let p be the number of trees Wangari plants, and h be the time she spends planting them in hours.

We have been given that Wangari plants trees at a constant rate of 12 trees every 3 hours.

Let us find number of trees planted in 1 hour by dividing 12 by 3.

$\text{Number of trees planted in 1 hour}=\frac{12\text{ plants}}{3\text{ hour}}$

$\text{Number of trees planted in 1 hour}=4\frac{\text{ plants}}{\text{ hour}}$

We can represent this information as: $p=4h$

Therefore, the equation $p=4h$ relates the number of trees (p) Wangari plants, and the time (h) she spends planting them in hours.

3 0

4 years ago

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