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hodyreva [135]
4 years ago
5

What is 30 to the power of 3 is?

Mathematics
2 answers:
Anna11 [10]4 years ago
8 0
30 to the power of 3 is 27000
Vikki [24]4 years ago
6 0
What is 30^{3} ?

Well, exponents are the amount of times the base number multiplies by itself

So 30^{3} is 30×30×30=27,000

Answer: 27,000

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What expression are 5 times as large as 184 + 213.
Hunter-Best [27]

Answer. 1985

Step-by-step explanation:

You add 184 and 213 and then get 387 then × it by 5 and get 1985

8 0
3 years ago
Is 2/12 a terminating term? ?
boyakko [2]
Hi pupil here's your answer ::

____________________________

This term 2/11 is not a terminating one because when we divide 2 by 11 the answer is 0.1818181818181818181818181818181818181818...........and so on. So the answer is non obtaining that means that it is an non terminating term.

____________________________

hope that it helps. . . . . .
3 0
3 years ago
Can someone help me with 20
Alexxandr [17]
D is subset of Z, so D∩Z=D. hope it helps.
7 0
3 years ago
One leg of a right triangle is 7 inches longer than the other leg, and the hypotenuse is 35 inches. Find the lengths of the legs
lilavasa [31]

Answer: 21, 28

Step-by-step explanation:

  • Side #1 = x
  • Side #2 = x + 7
  • Hypotenuse = 35

Use the Pythagorean Theorem a^{2}+b^{2}=c^{2}:

  • a = x
  • b = x + 7
  • c = 35

Substitute in the values & solve:

x^{2}+(x+7)^{2}=35^{2}\\x^{2}+x^{2}+14x+49=1225\\2x^{2}+14x+49-1225=0\\2x^{2}+14x-1176=0\\2(x^{2}+7x-588)=0\\2(x + 28)(x - 21)=0\\x_{1}=-28, x_{2}=21

<em><u>-28 is not a possible solution since you can't have negative inches...</u></em>

  • a = x = 21
  • b = x + 7 = 21 + 7 = 28
  • c = 35
6 0
3 years ago
given that (y+2) (y+3) and (2y^2+1) are consecutive terms of an arithmetic progression, find the possible value of y​
mafiozo [28]

Answer:

<em>-3/2 and 1</em>

Step-by-step explanation:

Given the  arithmetic sequence  (y+2) (y+3) and (2y²+1), the common difference is gotten by taking the difference in their terms. For example if we have 3 terms T1, T2, T3... the common difference d = T2-T1 = T3-T2

From the  sequence given;

T1 = y+2, T2 = y+3 and T3 = 2y²+1

d = y+3-(y+2) = 2y²+1- (y+3)

open the parenthesis

y+3-y-2 = 2y²+1- y-3

1 = 2y²+1- y-3

1 = 2y²- y-2

2y²- y-2-1 = 0

2y²- y-3 =0

Factorize the resulting expression

2y²- y-3 =0

2y²- 2y+3y-3 =0

2y(y-1)+3(y-1) = 0

(2y+3)(y-1) = 0

2y+3 = 0 and y-1 = 0

2y = -3 and y =1

y = -3/2 and 1

<em>Hence the possible values of y are -3/2 and 1</em>

8 0
3 years ago
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