Answer:
x=3
Step-by-step explanation:
2x/3−x/10=17/10
Multiply each side by 30 to get rid of the fractions
30( 2x/3−x/10)=(17/10)*30
Distribute
20x -3x = 51
Combine like terms
17x = 51
Divide by 17
17x/17 = 51/17
x=3
Answer:
x=4
Step-by-step explanation:
x^3-4x^2-16x+64
(x^2-16)(x-4)
x-4=0
+4 +4
x=4
x^2-16=0
+16 +16
x^2=16
√ x^2=√ 16
x=4
Hi :)
The mean is the average, and to take the average, they had to do this:
{students' minutes added together} ÷ 14 students = 133 minutes
This is basic pre-algebra; to find the total, we do the reverse of what they did. Since they divided by 14 to get 133, we're going to do the opposite. We're going to multiply 133 by 14 to get the total:
133 × 14 = 1862 minutes
Next question. The typical amount of time a student talked in a week was 133, and you're trying to find the typical amount of time in a day. There are 7 days in a week, so divide 133 by 7 to get the typical number of minutes in a day. (I won't do this for you-- you got this!)
Alright, so 19 students talked 171 minutes on average. Let's go back again and see what the total number of minutes were.
{total} ÷ 19 = 171
{total} = 171 × 19
{total} = 3249
But, hang on. They don't just want to know the total, they want to know the "mean number of minutes the additional five other students talked". That means we have to first subtract the 14 students' total from the 19 students' total to see what the difference is:
3249 - 1862 = 1387
So the five students added 1387 minutes to the average.
Divide 1387 by 5 to see the mean number of minutes per each of the five students.
You got this! Have fun!!
Combining like terms just means putting together all the same variables. On the left side, 5x + x + x are all like terms and yoh get a total of 7x. Then -6 - 2 is -8. Left side in total is 7x - 8. As for the right side, is "a" a variable too?
Answer:
C) both
Step-by-step explanation:
-4x+7=2y-3
Plug in
(2,1)
-4(2) +7 = 2(1)-3
-8 + 7 = 2 - 3
-1 = -1
So (2,1) is the solution
(5,-5)
-4(5) +7 = 2(-5)-3
-20 + 7 = -10 - 3
-13 = -13
So (5,-5) is the solution
Answer:
C) both
