No estoy segura pero 2.5 (half of the box that is 5cm)
Answer:
Kindly check explanation
Step-by-step explanation:
Given :
Sample size, n = 30
Tcritical value = 2.045
Null hypothesis :
H0: μ = 9.08
Alternative hypothesis :
H1: μ≠ 9.08
Sample mean, m = 8.25
Samole standard deviation, s = 1.67
Test statistic : (m - μ) ÷ s/sqrt(n)
Test statistic : (8.25 - 9.08) ÷ 1.67/sqrt(30)
Test statistic : - 0.83 ÷ 0.3048988
Test statistic : - 2.722
Tstatistic = - 2.722
Decision region :
Reject Null ; if
Tstatistic < Tcritical
Tcritical : - 2.045
-2.722 < - 2.045 ; We reject the Null
Using the α - level (confidence interval) 0.05
The Pvalue for the data from Tstatistic calculator:
df = n - 1 =. 30 - 1 = 29
Pvalue = 0.0108
Reject H0 if :
Pvalue < α
0.0108 < 0.05 ; Hence, we reject the Null
Answer:
Two non zero vectors, a and b are parallel when they are scalar multiples of each other such that a = c·b where c is a scalar quantity.
Therefore, in order to find a vector that is parallel to the vector, b = (-2, -1), we multiply the vector, b by a scaler quantity
Step-by-step explanation:
Given that the vector b = (-2, -1) can be written as follows;
b = -2·i - j, we have;
= √((-2)² + (-1)²) = √5
Therefore, we have;
The coordinates of the endpoint of the vector are (-2, 0) and (0, -1)
Therefore, the slope of the vector = (-1 - 0)/(0 - (-2)) = -1/2
The slope of parallel vectors are equal, which gives the slope of the parallel vector = -1/2 = (λ × (-1 - 0))/(λ ×(0 - (-2))
Therefore, a parallel vector is obtained from a vector by multiplying with a scaler product.
Answer:
65
Step-by-step explanation: