Answer:
a) Depth changing rate of change is 
, When the water is 6 meters deep
b) The width of the top of the water is changing at a rate of 
, When the water is 6 meters deep
Step-by-step explanation:
As we can see in the attachment part II, there are similar triangles, so we have the following relation between them 
, then 
.
a) As we have that volume is 
, then 
, so we can derivate it 
due to the chain rule, then we clean this expression for 
and compute with the knowns 
, is the depth changing rate of change when the water is 6 meters deep.
b) As the width of the top is 
, we can derivate it and obtain 
The width of the top of the water is changing, When the water is 6 meters deep at this rate
Answer:
Ok, we have a system of equations:
6*x + 3*y = 6*x*y
2*x + 4*y = 5*x*y
First, we want to isolate one of the variables,
As we have almost the same expression (x*y) in the right side of both equations, we can see the quotient between the two equations:
(6*x + 3*y)/(2*x + 4*y) = 6/5
now we isolate one off the variables:
6*x + 3*y = (6/5)*(2*x + 4*y) = (12/5)*x + (24/5)*y
x*(6 - 12/5) = y*(24/5 - 3)
x = y*(24/5 - 3)/(6 - 12/5) = 0.5*y
Now we can replace it in the first equation:
6*x + 3*y = 6*x*y
6*(0.5*y) + 3*y = 6*(0.5*y)*y
3*y + 3*y = 3*y^2
3*y^2 - 6*y = 0
Now we can find the solutions of that quadratic equation as:
So we have two solutions
y = 0
y = 2.
Suppose that we select the solution y = 0
Then, using one of the equations we can find the value of x:
2*x + 4*0 = 5*x*0
2*x = 0
x = 0
(0, 0) is a solution
if we select the other solution, y = 2.
2*x + 4*2 = 5*x*2
2*x + 8 = 10*x
8 = (10 - 2)*x = 8x
x = 1.
(1, 2) is other solution
Answer: the the 2nd circular one
Step-by-step explanation: Functions can't just go in a circle, they will repeat the x value
Answer:
The answer is c
Step-by-step explanation:
Answer:
the 4th option
Step-by-step explanation:
x is greater than -6 but less than 2
