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3 years ago

Pls help

Mathematics

1 answer:

denis-greek [22]3 years ago

7 0

Answer:

C I think

Step-by-step explanation:

Hehehehehehe

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Step-by-step explanation:

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Answer:

$(a+b)^n ={n \choose 0}a^{(n)}b^{(0)} + {n \choose 1}a^{(n-1)}b^{(1)} + {n \choose 2}a^{(n-2)}b^{(2)} + ..... +{n \choose n}a^{(0)}b^{(n)}$

Step-by-step explanation:

The Given question is INCOMPLETE as the statements are not provided.

Now, let us try and solve the given expression here:

The given expression is: $(a +b)^n, n > 0$

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Here, $(a+b)^n = \sum_{k=0}^{n}{n \choose k}a^{(n-k)}b^{(k)}$

or, on simplification, the terms of the expansion are:

$(a+b)^n ={n \choose 0}a^{(n)}b^{(0)} + {n \choose 1}a^{(n-1)}b^{(1)} + {n \choose 2}a^{(n-2)}b^{(2)} + ..... +{n \choose n}a^{(0)}b^{(n)}$

The above statement holds for each n > 0

Hence, the complete expansion for the given expression is given as above.

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3 years ago

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Answer:

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Step-by-step explanation:

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(but in real life this is what happens. Its not fair).

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Here’s the answers
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