Answer:
I think it would be 873.
Step-by-step explanation:
You just have to calculate.
Answer:
A sample of 601 bricks will be needed.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
The margin of error is:
95% confidence level
So , z is the value of Z that has a pvalue of , so .
How large a sample will we need?
A sample of n bricks will be needed.
n is found when M = 0.04.
We have no estimate for the proportion of defective bricks, so we work with the worst case scenario, which is
Rounding up
A sample of 601 bricks will be needed.
There are 16 ounces in one pound. So we do 7 divided by 16 to get our answer.
7 / 16 = 0.4375 ≈ 0.4 lbs
7 oz is approximately 0.4 lbs.
Answer:
<em>The actual length of the ship is 337.6 m</em>
<em>The actual width of the ship is 65.6 m</em>
Step-by-step explanation:
<u>Scaling</u>
The scale model of the aircraft carrier USS Eisenhower is 42.2 cm long and 8.2 cm wide when using the scale factor of 1 cm=800 cm.
Since we are required to express the real measures in meters, the scale factor is 1 cm = 8 m.
The actual length of the ship is:
42.2*8=337.6 m
The actual width of the ship is:
8.2*8=65.6 m
What goes in goes out. This means none of the current is lost. So if 0.7amps+0.68amps+0.47amps = 1.85 amps comes in, then 1.85 amps goes out. So far we have 0.8 amps+0.55 amps going out= 1.35 amps. This means we need an additional 1.85-1.35amps going out= 0.5 amps for the third outgoing current. Cheers!