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Andreyy89
3 years ago
12

determine the decimal equivalent for 1/11 2/11 and 3/11. Use a pattern to mentally determine the decimal and equivalent for 7/11

and 8/11
Mathematics
1 answer:
Andrews [41]3 years ago
6 0
In a calculator:
1/11 = 0.09090909.....
2/11 = 0.18181818.....
3/11 = 0.27272727.....
(Notice: bold numbers are multiples of 9)
There is a patern, for each multiple of 1/11 (which is equivalent to the numerator), we get a "0.", followed by the same multiple of 9 as the multiple of 11, displayed as two digits, which are repeated infinitely;
We can apply this principle to find the decimal equivalents of the two other fractions as they have the same denominator, so:

For 7/11:
We do:
7 * 9 = 63
So:
7/11 = 0.63636363..... (= 0.63 recurring)

For 8/11:
8 * 9 = 72
So:
8/11 = 0.72727272..... (= 0.72 recurring)
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A cylindrical soup can has a diameter of 3.6 in. and is 6.4 in. tall. Find the volume of the can.
arsen [322]
<h2>⚘Your Answer:------</h2>

<h3><u>Given</u><u> </u><u>Information</u><u>:</u></h3>

  • <u>Diameter of can</u>:- 3.6 cm
  • <u>Height of</u><u> </u><u>can</u><u>:</u><u>-</u> 6.4 cm

<h3><u>To</u><u> </u><u>Find</u><u> </u><u>Out</u><u>:</u></h3>

  • <u>Volume</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>Can</u><u>.</u>

<h3><u>Solution</u><u>:</u></h3>

Radius = (Diameter/2)

ㅤㅤㅤㅤ3.6 cm/2

ㅤㅤㅤㅤ1.8 cm

<u>So</u><u>,</u><u> </u><u>Radius</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>soup</u><u> </u><u>can</u><u> </u><u>is</u> 1.8 cm.

Volume øf cylinder = Volume øf can

Volume of cylinder = π r²h

(π = 22/7)

(r = radius = 1.8 cm)

(h = height = 6.4 cm

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ= 22/7×(1.8 cm)²× 6.4 cm

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ= 22/7× 3.24 cm² × 6.4 cm

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ= 22/7 × 20.736 cm³

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ= (456.192/7) cm³

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ= 65.17 cm³

So, the Volume of the soup can is 65.17 cm³

ㅤㅤㅤㅤㅤㅤㅤㅤ⚘Thank You

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2 years ago
What is the measure of angle B in degrees?
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Answer:

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3 years ago
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3 years ago
the numbers 2-12 are written on cards and placed in the bag.what is the probability of picking an even number then replacing it
lorasvet [3.4K]

We have the cards numbered as 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, and 12.

Sample number is, n(S)=11.

We pick a card and want to get even number like 2, 4, 6, 8, 10, and 12.

Probability of picking an even number would be :-

P(even numbers) = \frac{6}{11}

Now we replace the card and want to get a 7 in second attempt.

Probability of picking a 7 would be :-

P(number 7) = \frac{1}{11}

Now Probability of this event = P(even numbers) × P(number 7)

Probability = (\frac{6}{11} )(\frac{1}{11} ) = \frac{6}{121}

So final answer is \frac{6}{121}.

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