Do you want a general solution or from 0 <= x < 2pi?
tan^2(2x) - 1 = 0
tan^2(2x) = 1
Take the square root of both sides,
tan(2x) = +/- 1
Two equations:
tan(2x) = 1
tan(2x) = -1
Solve each equation.
tan(2x) = 1, 2x = {pi/4, 5pi/4, 9pi/4, 13pi/4},
x = { pi/8, 5pi/8, 9pi/8, 13pi/8 }
tan(2x) = -1, 2x = { 3pi/4, 7pi/4, 11pi/4, 15pi/4 },
x = { 3pi/8, 7pi/8, 11pi/8, 15pi/8}
So for solutions within [0, 2pi),
x = {pi/8, 3pi/8, 5pi/8, 7pi/8, 9pi/8, 11pi/8, 13pi/8, 15pi/8 }
Answer:
Step-by-step explanation:
<h3>Solution</h3>
- 6 - 2n - 5< -11
- 1 - 2n < -11
- -2n < -12
- n > 6
<h3>Check</h3>
- n = 10
- 6 - 2*10 - 5 < -11
- 6 - 20 - 5 < -11
- -19 < -11
Graph is the line segment of the right from point 6 not including 6
Answer:
6 units
Step-by-step explanation:
The distance between two points can be calculated with the formula
However, since (0, 2) and (0, 8) have the same x coordinate of 0, the distance between them is the difference in their y-coordinates.
Distance between (0, 2) and (0, 8)
= 8 -2
= 6 units
Answer:
x=5
Step-by-step explanation:
JK+KL=JL
(2x)+(x-6)=(9)
calculate for x!
x=5