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3 years ago

Help!! problem w/ inequalities!!

Mathematics

2 answers:

OLga [1]3 years ago

7 0

Subtracting 5 from both sides will be your best choice.

For instance, your problem states x + 5 ≥ 10

Now to isolate x you will need to get rid of the 5. Since a addition sign is before 5 we will need to use the subtraction property to isolate x. It will look like so,

x + 5 ≥ 10

-5 -5

You will be left with x ≥ 5.

Hope this helped! :)

Vikentia [17]3 years ago

5 0

Subtract 5 from both sides!!

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I need help ASAP -2x^2+x 9-25x^2+8x X^5+x^3-x^2-1

nika2105 [10]

Answer:

For $-2x^2+x$ , Leading coefficient is -2, Degree is 2, Constant term is 0

For $9-25x^2+8x$ , Leading coefficient is -25, Degree is 2, Constant term is 9

For $x^5+x^3-x^2-1$ , Leading coefficient is 1, Degree is 5, Constant term is -1

Step-by-step explanation:

Given:

Polynomials:

$-2x^2+x\\9-25x^2+8x\\x^5+x^3-x^2-1$

To find: leading coefficient, constant term and degree

Solution:

Leading coefficient is the coefficient of the variable with the highest power.

Degree is the highest power of the variable.

The term of degree 0 is the constant term of a polynomial.

For $-2x^2+x$ ,

Leading coefficient is -2

Degree is 2

Constant term is 0

For $9-25x^2+8x$

Leading coefficient is -25

Degree is 2

Constant term is 9

For $x^5+x^3-x^2-1$

Leading coefficient is 1

Degree is 5

Constant term is -1

4 0

3 years ago

Product of 100 and sum of 25

ddd [48]

Answer:

100*25

Step-by-step explanation:

sum of 25=25

6 0

2 years ago

My son has the following missing number pattern to solve.

melisa1 [442]

The only complete pattern is the middle one
we see that 38-29=9
so the middle number minus the first number equals the third number
for the last row
21-1=20 so you have 1 21 20
for the first one

17- ?=37
54-17=37 54 17 37

6 0

3 years ago

Read 2 more answers

Can somebody help me with this please?

Svetach [21]

Multiply both sides by -4/7
$x = 40 \times ( \frac{ - 4}{7} ) \\ x = \frac{ - 160}{7}$

7 0

3 years ago

What does Inductory mean

timofeeve [1]

Serving to induct or bring in; introductory

8 0

3 years ago