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Delicious77 [7]
3 years ago
7

Help please!!! I dont understand these questionscurrently attaching photos dont delete

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
3 0

Answer:

  1. b/a
  2. 16a²b²
  3. n¹⁰/(16m⁶)
  4. y⁸/x¹⁰
  5. m⁷n³n/m

Step-by-step explanation:

These problems make use of three rules of exponents:

a^ba^c=a^{b+c}\\\\(a^b)^c=a^{bc}\\\\a^{-b}=\dfrac{1}{a^b} \quad\text{or} \quad a^b=\dfrac{1}{a^{-b}}

In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)

__

1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.

\dfrac{b^{-2}}{ab^{-3}}=\dfrac{b^{-2-(-3)}}{a}=\dfrac{b}{a}

__

2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.

\left(\dfrac{1}{4ab}\right)^{-2}=\dfrac{1}{4^{-2}a^{-2}b^{-2}}=16a^2b^2

__

3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.

\left(\dfrac{4mn}{m^{-2}n^6}\right)^{-2}=\left(4m^{1-(-2)}n^{1-6}}\right)^{-2}=\left(4m^3n^{-5}}\right)^{-2}\\\\=4^{-2}m^{-6}n^{10}=\dfrac{n^{10}}{16m^6}

__

4. This works the same way the previous problem does.

\left(\dfrac{x^{-4}y}{x^{-9}y^5}\right)^{-2}=\left(x^{-4-(-9)}y^{1-5}\right)^{-2}=\left(x^{5}y^{-4}\right)^{-2}\\\\=x^{-10}y^{8}=\dfrac{y^8}{x^{10}}

__

5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.

\dfrac{m^7n^3}{mn^{-1}}=\dfrac{m^7n^3n}{m}

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Answer:

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Step-by-step explanation:

Eliminate parentheses and collect terms:

  3x -12 +5 -x = 2x -7

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This is true for any value of x. There are an infinite number of solutions.

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3 years ago
Find y when x = 3 of the equation for y=2x+12
ser-zykov [4K]

Answer:

y = 18

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

Step-by-step explanation:

<u>Step 1: Define</u>

y = 2x + 12

x = 3

<u>Step 2: Evaluate</u>

  1. Substitute in <em>x</em>:                                                                                                y = 2(3) + 12
  2. Multiply:                                                                                                           y = 6 + 12
  3. Add:                                                                                                                 y = 18
3 0
3 years ago
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Use the distributive property to simplify 7(2a + 5).
Vinil7 [7]

Answer:

14a+35

Step-by-step explanation:

7×2a=14a

7×5=35

=14a+25

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Answer:

<em> </em><em>a </em><em>+</em><em> </em><em>5</em><em>b</em><em> </em><em>+</em><em> </em><em>5</em><em>c</em>

Step-by-step explanation:

here's your solution

=> 3a + 4b + 5c +(-2a) + b

=> solve for like term

=> 3a - 2a + 4b + b + 5c

=> a + 5b + 5c

hope it helps

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