In the game of roulette, a player can place a $4 bet on the number 10 and have a 1/38 probability of winning. If the metal ball
lands on 10, the player gets to keep the $4 paid to play the game and the player is awarded an additional $140. Otherwise, the player is awarded nothing and the casino takes the player’s $4. What is the expected value of the game to the player? If you played the game 1000 times, how much would you expect to lose?
A whole number that would support Cindys claim would be 2 because if u do the ,math it would be 8/24 which would be .333 repeating which is simplify to 1/3 and i do not know a number that would not work.
