Answer:
-4 ≤ f () ≤ 4
Step-by-step explanation:
The range of a function is the allowed y-values of the function.
We can simply look at the periodic function below and see that the y-value ranges from a negative 4 to a positive 4. It oscillates betwen -4 and 4. That is the range.
We can say -4 ≤ f () ≤ 4
Last answer choice is right.
*** <u>NOTE:</u> it is a type, not "0", rather ""
Answer:
No, because the distance from the origin to point (7 , -7) is greater than the radius of the circle ⇒ 3rd answer
Step-by-step explanation:
From the graph of the circle
∵ The center of the circle F is at the origin
∴ F is (0 , 0)
∵ The circle passes through point (7 , 0)
- The length of the radius of the circle is the distance between
the center of the circle and a point on the circle
∴ r is the distance between points (0 , 0) and (7 , 0)
∴
∴ The length of the radius of the circle is 7 units
Let us find the distance between point (7 , -7) and the origin (0 , 0)
∵ The distance =
∵ r = 7
∵ > 7
∴ The distance is greater than the radius of the circle
∴ Point (7 , -7) lies outside the circle
The correct answer is:
No, because the distance from the origin to point (7 , -7) is greater than the radius of the circle
<em>Your answer is not correct, the correct answer is the 3rd answer</em>