Answer:
Hopes it helps
Step-by-step explanation:
The Quadratic Polynomial is
2 x² +x -4=0
Using the Determinant method to find the roots of this equation
For, the Quadratic equation , ax²+ b x+c=0
(b) x²+x=0
x × (x+1)=0
x=0 ∧ x+1=0
x=0 ∧ x= -1
You can look the problem in other way
the two Quadratic polynomials are
2 x²+x-4=0, ∧ x²+x=0
x²= -x
So, 2 x²+x-4=0,
→ -2 x+x-4=0
→ -x -4=0
→x= -4
∨
x² +x² +x-4=0
x²+0-4=0→→x²+x=0
→x²=4
x=√4
x=2 ∧ x=-2
As, you will put these values into the equation, you will find that these values does not satisfy both the equations.
So, there is no solution.
You can solve these two equation graphically also.
Answer:
87/3
Step-by-step explanation:
Here we are given the expression:
Now we have to find the value of this expression when x equals 9.
So plugging the value of x as -9 in the given expression:
=87/3
So on evaluating we get the value of expression as 87/3.
Answer:
Jimmy; 26
Step-by-step explanation:
PEMDAS
Parentheses Exponents Multiplication Division Addition Subtraction
6 + 4 * 10 / 2 = 6 + 40 / 2
6 + 40 / 2 = 6 + 20
6 + 20 = 26
26
Answer:
A reflection over the line x=3
Step-by-step explanation:
