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3 years ago

(0,-2), (-5, -1) Please helo

Mathematics

2 answers:

PolarNik [594]3 years ago

6 0

Answer:

d= 5.09902

Step-by-step explanation:

Use the distance formula: $d=\sqrt{(x_{2} -x_{1} )^{2} +(y_{2} -y_{1})^{2} }$

Substitute into the formula: $d= \sqrt{(-5-0)^2+(-1-(-2))^2}$

Simplify: $d= \sqrt{(-5)^2+(1)^2}$

Multiply: $d= \sqrt{25+1}$

Add: $d= \sqrt{26}$

Square root is: d= 5.09902

loris [4]3 years ago

5 0

Answer:

5.5 units

Step-by-step explanation:

I'm not 100% sure if this is right, since it could be 5 or 6, but since there is a slight diagonality to it, i would say 5.5 units.

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When she just turned 22, Rae purchased 145 shares of Stock A for $25 per share; 87 shares of Stock B for $38 per share; 46 share

Damm [24]

Answer:

170

Step-by-step explanation:

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8 0

3 years ago

Given m∥n the value of x. (8x-20) (8x+8)

igomit [66]

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3 years ago

Select the correct answer.

nikdorinn [45]

Answer:

a negative linear association (C)

Re-Written Problem [Formatted]

Teams with varying numbers of players are playing a group card game. the time taken by each team to complete one game is given in the table. What is the relationship between the two variables?

Numbers of players on team are going to be 1, 2 , 3, 4, 5.

time taken to complete game (in minutes) 32, 26, 20, 14, 8

(Select the correct answer)

A. Positive linear association

B. Exponential relationship

C. Negative linear association

D. No relationship

----------------------------------------------------------------------------------

Step-by-step explanation:

Lower x values (numbers of players on team) are correlated with higher y values (time taken to complete game)

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<em>[note: I know which values are x and y because of a cause-and-effect relationship. x causes y. number of players causes a change in minutes {it wouldn't make sense for the number of time it took to cause the number of players} ]</em>

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So, if we were to graph this relationship, we would see a downward-slope / negative slope of a line, because greater x-values are associated with lower y-values.

So, you would see a negative line, showing a negative linear association.

5 0

2 years ago

Use an algebraic equation to find the measure of each angle that is represented in terms of X

professor190 [17]

Answer:

16, 74

Step-by-step explanation:

3x +10 + 12x +50 = 90

15x + 60 = 90

15x = 90 -60

15x = 30

x = 30/15

x = 2

3x + 10 = 3*2 +10 = 6 +10 = 16

12x + 50 = 12*2 +50 = 24 + 50 = 74

5 0

3 years ago

Write a polynomial f(x) that satisfies the given conditions.

patriot [66]

Answer:

$f(x) = (x-4)(x-\frac{1}{2})^2 = x^3-5x^2+4.25x -1$

Step-by-step explanation:

Recall, if we have a polynomial of the form $(x-a)^k \cdot (x-b)^m$ , then we say that a is a zero of multiplicity k and b is a zero of multiplicty m. For example, in the polynomial of the form $(x+5)^10(x-2)^3$ -5 is a zero of multiplicity 10 and 2 is a zero of multiplicity 3. If we want to know the degree of the polynomial, just add the multiplicity of both zeros (13 in our example).

In this case, we know that the degree of our polynomial should be at least 3(multiplicity 2 and multiplicity 1). So, lets take the polynomial of the form

$f(x)=(x-a)(x-b)^2)$ .

In here, a is a zero with multiplicity 1 and b is a zero with multiplicity 2. We are also given that

$f(0) = -1 = (0-a)(0-b)^2 = -a\codt b^2$ .

Which implies that $1 = a\cdot b^2$ . Since the square of any number is a positive number, it must happen that a>0. So, we have that

$b= \pm \sqrt[]{\frac{1}{a}}$ .

We can choose any value of a and solve for b. Let us choose a=4. So we can have b=1/2 or b=-1/2. Let's use b=1/2. So our polynomial would be

$f(x) = (x-4)(x-\frac{1}{2})^2 = x^3-5x^2+4.25x -1$

which we can easily check that f(0)=-1.

6 0

4 years ago