Order these from least to greatest: 350/100 0.351 and 27%

PLEASE HELP!<br> *multiple choice*<br> List the sides in order from shortest to longest.

Amiraneli [1.4K]

Answer:

I think it's a

I'm not that sure tho

4 0

3 years ago

Researchers are interested in studying how to maintain weight loss. Based on a survey of almost 3000 adults, researchers Wyatt e

Mamont248 [21]

Answer:

No , the cause and effect can be finished up through analyses as it were.

What we have in the inquiry is only an observational investigation where we basically study 3000 grown-ups and attempt to outline the outcomes with no trial proof.

Imagine a scenario in which individuals who had breakfast normally were inclined to maintain their weight reduction, for sure if individuals who keep up weight reduction will in general have breakfast routinely.

henceforth the circumstances and logical results relationship cannot be built up

So as to do so , one must lead measurable trials, for example, autonomous example t test or ANOVA examination

6 0

3 years ago

Find the work required to move an object in the force field F = ex+y <1,1,z> along the straight line from A(0,0,0) to B(-1

storchak [24]

Answer:

Work = e+24

F is not conservative.

Step-by-step explanation:

To find the work required to move an object in the force field

$\large F(x,y,z)=(e^{x+y},e^{x+y},ze^{x+y})$

along the straight line from A(0,0,0) to B(-1,2,-5), we have to parameterize this segment.

Given two points P, Q in any euclidean space, you can always parameterize the segment of line that goes from P to Q with

r(t) = tQ + (1-t)P with 0 ≤ t ≤ 1

so

r(t) = t(-1,2,-5) + (1-t)(0,0,0) = (-t, 2t, -5t) with 0≤ t ≤ 1

is a parameterization of the segment.

the work W required to move an object in the force field F along the straight line from A to B is the line integral

$\large W=\int_{C}Fdr$

where C is the segment that goes from A to B.

$\large \int_{C}Fdr =\int_{0}^{1}F(r(t))\circ r'(t)dt=\int_{0}^{1}F(-t,2t,-5t)\circ (-1,2,-5)dt=\\\\=\int_{0}^{1}(e^t,e^t,-5te^t)\circ (-1,2,-5)dt=\int_{0}^{1}(-e^t+2e^t+25te^t)dt=\\\\\int_{0}^{1}e^tdt-25\int_{0}^{1}te^tdt=(e-1)+25\int_{0}^{1}te^tdt$

Integrating by parts the last integral:

$\large \int_{0}^{1}te^tdt=e-\int_{0}^{1}e^tdt=e-(e-1)=1$

and

$\large \boxed{W=\int_{C}Fdr=e+24}$

To show that F is not conservative, we could find another path D from A to B such that the work to move the particle from A to B along D is different to e+24

Now, let D be the path consisting on the segment that goes from A to (1,0,0) and then the segment from (1,0,0) to B.

The segment that goes from A to (1,0,0) can be parameterized as

r(t) = (t,0,0) with 0≤ t ≤ 1

so the work required to move the particle from A to (1,0,0) is

$\large \int_{0}^{1}(e^t,e^t,0)\circ (1,0,0)dt =\int_{0}^{1}e^tdt=e-1$

The segment that goes from (1,0,0) to B can be parameterized as

r(t) = (1-2t,2t,-5t) with 0≤ t ≤ 1

so the work required to move the particle from (1,0,0) to B is

$\large \int_{0}^{1}(e,e,-5et)\circ (-2,2,-5)dt =25e\int_{0}^{1}tdt=\frac{25e}{2}$

Hence, the work required to move the particle from A to B along D is

e - 1 + (25e)/2 = (27e)/2 -1

since this result differs from e+24, the force field F is not conservative.

6 0

4 years ago

PLEASE HELP YOU WILL GIVE YOU POINTS!!!

Dafna1 [17]

Answer:

The Answer is the 2nd Table from the top

Step-by-step explanation:

Total of 30 men, 20 watched 10 didn't

Total of 80 participants, 45 Watched, 35 Didn't

The Female participants had to add up to fill in the bottom rows.

8 0

3 years ago

Determine if xy is tangent to circle z

Kisachek [45]

Hi there!

When a segment is tangent to a circle, it is perpendicular to the radius. If you're given measurements, like the image below, you can use the pythagorean theorem to determine if the triangle is a right triangle. If the triangle is right, then the segment is tangent to the circle.

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!

4 0

4 years ago