Question

A stadium has 55,000 seat seat sale for $25 in section a $20 in section B and $15 in section see the number of seats in section 8 equals the total number of seats in section B and C supposed to Stadium takes in 1,171,000 from each sold out event. How many seats does each section hold?

Answer 1

Answer:

• A: 27500
• B: 14200
• C: 13300

Step-by-step explanation:

Since the number of A seats is equal to the number of non-A seats, that number is half the total, or 55000/2 = 27,500.

When the stadium is sold out, the revenue from the Section A seats is ...

  $25 × 27,500 = $687,500

That means the revenue from sections B and C will be ...

  $1,171,000 -687,500 = $483,500

If "b" represents the number of Section B seats, then (27,500-b) will be the number of Section C seats. The revenue equation for these seats is ...

  $20×b + $15×(27500-b) = $483,500

  5b = 71000 . . . . . . . . . . . simplify, subtract $412,500, divide by $

  b = 14,200 . . . . . . . . . . . . divide by 5; number of section B seats

  27500-b = 13,300 . . . . . .section C seats

Each section holds ...

• A: 27,500 seats
• B: 14,200 seats
• C: 13,300 seats