Answer:
The area of the region inside the circumcircle of the triangle but outside the triangle is
![A=\frac{27}{4}[\pi-3\sqrt{3}]\ units^2](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B27%7D%7B4%7D%5B%5Cpi-3%5Csqrt%7B3%7D%5D%5C%20units%5E2)
Step-by-step explanation:
see the attached figure to better understand the problem
step 1
Find the area of triangle
we have an equilateral triangle
Applying the law of sines
where b is the length side of the equilateral triangle
we have
step 2
Find the area of circle
The area of the circle is equal to
The formula to calculate the radius of the circumcircle of the triangle equilateral is equal to
where b is the length side of the equilateral triangle
we have
substitute
Find the area
step 3
Find the area of the shaded region
we know that
The area of the region inside the circumcircle of the triangle but outside the triangle is equal to the area pf the circle minus the area of triangle
so
Simplify
Let me help you!
Looking at the visual, we can see five figures: KLM, 1, 2, 3, and 4.
Applying t<span>he rule T1, -4 RO, 180°(x, y) to rectangle KLMN - without even solving - just by merely observing, we can say (without a doubt) that the rectangle KLMN will most likely fall in the negative axis.
First rotation: -4 to the left.
Second rotation: -4 to the left.
Last rotation: -4 to the left making the last figure 3. <----- What we are looking for!
Therefore, the rectangle which shows the final image is figure 3 or rectangle 3.</span>
Answer:
Step-by-step explanation:
x + 3y = 9 this can be rewritten to x = 9 - 3y
and substitute the equation to 2x - y = 4
it becomes
2 (9 - 3y) - y = 4
hope it helps
Answer:
7048/637
Step-by-step explanation:
10 8/13 + 4 24/49
138/13 + 220/49
taking LCM
(138*49 + 220*13) / (13*49)
7048 / 637
Answer:
its h
Step-by-step explanation:
3/4th of 16 is 12
