The volume of the frustum is volume of the whole cone(A) minus the smaller cone(B) which is would give the volume of frustum(C) = 256cm³
<h3>Calculation of a frustum</h3>
The volume of cone A V=πr²h/3
Where radius = 20cm
The volume of cone B = V=πr²h/3
Where radius = 12cm
Therefore volume of frustum =
V=π * 20² * h/3 - π * 12² *h/3
The variables will cancel out each other
V = 20² - 12²
V = 400- 144
V = 256cm³
Therefore, the volume of the frustum(C) = 256cm³
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Y=mx+b so this means you’ll get the correct answer
Answer:
<h3> 10,450</h3>
Step-by-step explanation:
21-13=8 and 29-21=8
So this is aritmetic series where a₁ = 13, and r = 8
Sum of the first n terms:
Answer:
1/6
Step-by-step explanation:
