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Artemon [7]
3 years ago
12

What does the graph of f(x)=(3x-5)(x+9) cross the x axis

Mathematics
1 answer:
Oduvanchick [21]3 years ago
6 0
Hello.

Firstly, we need to simplify the function:

\mathsf{f(x) = (3x - 5) \times (x + 9)} \\ \\ \mathsf{f(x) = 3x^{2} - 5x + 27x - 45} \\ \\ \mathsf{f(x) = 3x^{2} + 22x - 45}

The graph crosses the 'x' axis when y = 0. Ergo:

\mathsf{3x^{2} + 22x - 45 = 0} \\ \\ \\ \mathsf{\triangle = b^{2} - 4ac} \\ \\ \mathsf{\triangle = 484 - 4 \times 3 \times (-45)} \\ \\ \mathsf{\triangle = 484 + 540} \\ \\ \mathsf{\triangle = 1024} \\ \\ \\ \mathsf{x = \dfrac{-b \pm \sqrt{\triangle}}{2a}} \\ \\ \\ \mathsf{x_{1} = \dfrac{-22 + 32}{6} = \dfrac{10}{6} = \dfrac{5}{3}} \\ \\ \\ \mathsf{x_{2} = \dfrac{-22 - 32}{6} = \dfrac{-54}{6} = -9}

Therefore, the graph crosses the x axis when x = -9 and 5/3.

Hope I helped.
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From there, solve for x.

First get x on one side, by using the addition property of equality.

x-1=-2x+5
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Isolate x by adding 1.
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Lastly get x all by itself by dividing each side by 3.
x=2

You can now substitute your x-value, 2, into one of the equations (or both, if you wish; either one will result in the same answer.)

y=x-1
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