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masya89 [10]
3 years ago
15

Students at Hampton Middle School sold T-shirts as a school fundraiser. Sylvie asked 12 random seventh-grade students how many T

-shirts they sold for the fundraiser. The number of T-shirts each student sold is listed below. 3, 4, 8, 5, 2, 5, 0, 5, 3, 4, 3, 7 What is the mean of the data set rounded to the nearest tenth? a. 4.0 shirts b. 4.1 shirts c. 4.5 shirts d. 4.9 shirts
Mathematics
2 answers:
AveGali [126]3 years ago
7 0

Answer:

b. 4.1 shirts

Step-by-step explanation:

Given data:

number of terms = 12

Terms given are 3, 4, 8, 5, 2, 5, 0, 5, 3, 4, 3, 7

Mean = (sum of terms)/ (number of terms)

Mean = (3 +4+ 8+ 5+2+5+0+ 5+ 3+ 4+3+ 7)/12

Mean = 49/12

Mean = 4.083

Mean = 4.1 (<em>to the nearest tenth)</em>

anyanavicka [17]3 years ago
5 0

Answer:

Answer is 4.1 shirts.

Step-by-step explanation:

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Answer:

\displaystyle \frac{dr}{dt}\approx 0,0112\ cm/sec

Step-by-step explanation:

<u>Rates of Change as Derivatives</u>

If some variable V is a function of another variable r, we can compute the rate of change of one with respect to the other as the first derivative of V, or

\displaystyle V'=\frac{dV}{dr}

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\displaystyle V=\frac{4}{3}\pi r^3

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\displaystyle \frac{dV}{dt}=9

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\displaystyle \frac{dV}{dt}=\displaystyle \frac{dV}{dr}\displaystyle \frac{dr}{dt}

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solving for \displaystyle \frac{dr}{dt}

\displaystyle \frac{dr}{dt}=\frac{\frac{dV}{dt}}{4\pi r^2}

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\displaystyle V=\frac{2048}{3}\pi\ cm^3

\displaystyle \frac{2048}{3}\pi=\frac{4}{3}\pi r^3

Simplifying and isolating r

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\displaystyle \frac{dr}{dt}=\frac{9}{4\pi 8^2}

\displaystyle \frac{dr}{dt}=\frac{9}{256\pi }

\displaystyle \frac{dr}{dt}\approx 0,0112\ cm/sec

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