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3 years ago

Which component of imc was not used in the jay-z and microsoft campaign described in the case?

Computers and Technology

1 answer:

Oliga [24]3 years ago

4 0

It should be advertisement. If not then it could be a search engine.

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A restaurant chain has several store locations in a city (with a name and zip code stored for each), and each is managed by one

bazaltina [42]

Answer:

The restaurant chain system consist of restaurant id, name, zipcode, manager id, menu list.

Manager; manager id, name, phone no, and store.

Menu; menu id, type, items and description.

Items; item id, price and description.

Explanation:

Please look at the attachment for the E. R diagram.

5 0

3 years ago

Suppose during a TCP connection between A and B, B acting as a TCP receiver, sometimes discards segments received out of sequenc

Shalnov [3]

Answer:

Yes

Explanation:

We known that TCP is the connection $\text{oriented}$ protocol. So the TCP expects for the target host to acknowledge or to check that the $\text{communication}$ session has been established or not.

Also the End stations that is running reliable protocols will be working together in order to verify transmission of data so as to ensure the accuracy and the integrity of the data. Hence it is reliable and so the data can be sent A will still be delivered reliably and it is in-sequence at B.

4 0

3 years ago

WILL GIVE BRAINIEST! Your users are young children learning their arithmetic facts. The program will give them a choice of pract

Ierofanga [76]

In python:

numA = [4, 1, 6, 10, 2, 3, 7, 9, 11, 12, 5, 8]

numB = [2, 12, 10, 11, 1, 3, 7, 9, 4, 8, 5, 6]

while True:

i = 0

userChoice = input("Adding or Multiplying? (a/m) ")

if userChoice == "a":

while i < len(numA):

answer = int(input("What is {} + {} ".format(numA[i],numB[i])))

if answer == numA[i] + numB[i]:

print("Correct!")

else:

print("That's incorrect. The right answer is {}".format(numA[i] + numB[i]))

i += 1

elif userChoice == "m":

while i < len(numA):

answer = int(input("What is {} * {} ".format(numA[i], numB[i])))

if answer == numA[i] * numB[i]:

print("Correct!")

else:

print("that's incorrect. The right answer is {}".format(numA[i] * numB[i]))

i += 1

4 0

3 years ago

Consider the following code segment, which is intended to set the Boolean variable inRange to true if the integer value num is g

Natasha_Volkova [10]

Answer:

Option d num = 50, min = 50, max = 50

Explanation:

Given the code segment:

boolean isBigger;
boolean isSmaller;
boolean inRange;
if (num < max)
{
isSmaller = true;
}
else {
isSmaller = false;
}
if (num > min)
{
isBigger = true;
}
else {
isBigger = false;
}
if (isBigger == isSmaller) {
inRange = true;
} else {
inRange = false;
}

If we have num = 50, min = 50 , max = 50, the condition num < max will be evaluated to false and therefore isSmaller is set to false.

The condition num > min will be evaluated to false as well and therefore isBigger is set to false.

Since isSmaller and isBigger are both false and therefore isBigger == isSmaller will be evaluated to true and set the inRange = true. This has violated the statement that if the integer value num is greater than min value and less than max value, then only set inRange to true. This is because num = 50 is neither greater than min nor less than max, it is supposedly not in range according to the original intention of the code design.

8 0

3 years ago

Write a program to print each item in the list of your favourite ice cream. please give proper answers.

timama [110]

Answer:

Python

Explanation:

#List Favorite ice-cream

ice_cream = ["Pistachio", "Cookies and cream", "Chocolate", "Banana split" , "Vanilla"]

for flavor in ice_cream:

print(flavor)

5 0

2 years ago