You would do the inside first so first you would do (8-3)x2 which would give u 10 then you would do (5x6)-5 which is 25 after tht u would add 25+10 which =35 after tht u would do 35/5 and u would get 7
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6 11/96
Sorry i cant explain just know its extremly hard and i recomend the app photo math its the best!
6) The number of sweets that tolu had is; 8 sweets
7) The number of sweets that Ogechi had is; 10 sweets
8) The number of sweets that Tamuno had is; 12 sweets
9) The number of sweets that Tamuno must give Tolu for them to have equal number is; 2 sweets
10) If Tolu gave four sweets to Tamuno, then Tamuno would have 4 times more sweets than Tolu
<h3>How to solve Algebra Word Problems?</h3>
Let the number of sweets that tolu had be x
Let the number of sweets that Ogechi had be y
Let the number of sweets that Tamuno had be z.
Thus;
x + y = 18 -----(1)
y + z = 22 -----(2)
x + y + z = 30 ------(3)
Substitute 22 for (y + z) in eq 3 to get;
x + 22 = 30
x = 30 - 22
x = 8
Substitute 18 for (x + y) in eq 3 to get;
18 + z = 30
z = 30 - 18
z = 12
y + z = 22
y + 12 = 22
y = 10
Read more about Algebra Word Problems at; brainly.com/question/21405634
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