BRIDGE CONSTRUCTION

(A) A small business ships homemade candies to anywhere in the world. Suppose a random sample of 16 orders is selected and each

Leviafan [203]

Following are the solution parts for the given question:

For question A:

$\to (n) = 16$

$\to (\bar{X}) = 410$

$\to (\sigma) = 40$

In the given question, we calculate $90\%$ of the confidence interval for the mean weight of shipped homemade candies that can be calculated as follows:

$\to \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{S}{\sqrt{n}}$

$\to C.I= 0.90\\\\\to (\alpha) = 1 - 0.90 = 0.10\\\\ \to \frac{\alpha}{2} = \frac{0.10}{2} = 0.05\\\\ \to (df) = n-1 = 16-1 = 15\\\\$

Using the t table we calculate $t_{ \frac{\alpha}{2}} = 1.753$ When $90\%$ of the confidence interval:

$\to 410 \pm 1.753 \times \frac{40}{\sqrt{16}}\\\\ \to 410 \pm 17.53\\\\ \to392.47 < \mu < 427.53$

So $90\%$ confidence interval for the mean weight of shipped homemade candies is between $392.47\ \ and\ \ 427.53$ .

For question B:

$\to (n) = 500$

$\to (X) = 155$

$\to (p') = \frac{X}{n} = \frac{155}{500} = 0.31$

Here we need to calculate $90\%$ confidence interval for the true proportion of all college students who own a car which can be calculated as

$\to p' \pm Z_{\frac{\alpha}{2}} \times \sqrt{\frac{p'(1-p')}{n}}$

$\to C.I= 0.90$

$\to (\alpha) = 0.10$

$\to \frac{\alpha}{2} = 0.05$

Using the Z-table we found $Z_{\frac{\alpha}{2}} = 1.645$

therefore $90\%$ the confidence interval for the genuine proportion of college students who possess a car is

$\to 0.31 \pm 1.645\times \sqrt{\frac{0.31\times (1-0.31)}{500}}\\\\ \to 0.31 \pm 0.034\\\\ \to 0.276 < p < 0.344$

So $90\%$ the confidence interval for the genuine proportion of college students who possess a car is between $0.28 \ and\ 0.34.$

For question C:

In question A, We are $90\%$ certain that the weight of supplied homemade candies is between 392.47 grams and 427.53 grams.
In question B, We are $90\%$ positive that the true percentage of college students who possess a car is between 0.28 and 0.34.

Learn more about confidence intervals:

brainly.in/question/16329412

7 0

2 years ago

If a car traveling at 75 mph west, changes its direction to east, does it accelerate?

antiseptic1488 [7]

Answer:

Yes, that's right, a change in the direction of motion results in an acceleration even if the moving object neither sped up nor slowed down. That's because acceleration depends on the change in velocity and velocity is a vector quantity — one with both magnitude and direction.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

What is the sequence of -1,2,7,14

Leya [2.2K]

Answer:

-1,2,7,14,25,36,49

Step-by-step explanation:

growing 2 from the series.First grown 3 then 5,7,9,11,13

4 0

2 years ago

I'LL GIVE BRAINLIEST FOR FASTEST CORRECT ANSWER AND YOU NEED TO EXPLAIN!!

Kazeer [188]

Answer + Explanation:

5 Cupcakes = $7.5.
How: First you see that 1 cupcake is $1.50. Multiply 5 by 1.50 and you get 7.50

18 Dollars = 12 Cupcakes
How: First you see that 1 cupcake is $1.50. Multiply 1.50 by numbers until you see 18.

18 Cupcakes = $27
How: First you see that 1 cupcake is $1.50. Multiply 18 by 1.50 and you get 27.

I Hope This Helped :D

6 0

1 year ago

Read 2 more answers

Write the extreme and middle terms of 5 : 80 :: 4 :64

Stells [14]

Answer:

The extremes are 5 and 64.

The middle terms are 80 and 4.

Step-by-step explanation:

Given the proportion:

5 : 80 :: 4 :64

To find:

The extreme and middle terms of the given proportion.

Solution:

The given statement is in proportion if and only if the product of extremes i.e. the numbers at both the ends is equal to the product of middle numbers.

OR

First number $\times$ Fourth number = Second number $\times$ Third number

First of all, let us check the two products.

5 $\times$ 64 = 320

And the second product:

80 $\times$ 4 = 320

The product is same therefore, the given numbers are in proportion.

The extreme terms are the first and the fourth numbers.

i.e. The extremes are 5 and 64.

The middle terms are 80 and 4.

7 0

2 years ago