7/12n is the answer to your question
Answer: 99% of confidence interval for the population proportion of employed individuals who work at home at-least once per week
//0.20113,0.20887[/tex]
Step-by-step explanation:
<u>step 1:-</u>
Given sample size n=200
of the 200 employed individuals surveyed 41 responded that they did work at home at least once per week
Population proportion of employed individuals who work at home at least once per week P = 
Q=1-P= 1-0.205 = 0.705
<u>step 2:-</u>
Now 
=0.0015
<u>step 3:-</u>
<u>Confidence intervals</u>
<u>using formula</u>


=0.20113,0.20887[/tex]
<u>conclusion:</u>-
99% of confidence interval for the population proportion of employed individuals who work at home at-least once per week
//0.20113,0.20887[/tex]
Multiple 15 times 8 and that is your answer
I believe it is a! hope this helps :-)
You can solve this by substitution:
x + y = -6
y = -6-x
Substitute for y in xy = -7:-
x(-6 - x) = -7
-x^2 - 6x = -7
x^2 + 6x - 7 = 0
(x + 7)(x - 1) = 0
so x = -7, 1
To find the values of y plug these va;ues of x into the equation x + y = -6:-
when x = -7, y = -6 + 7 = 1
when x = 1, y = -6 - 1 = -7
so answer is x = -7 and y = 1
and x = 1 and y = -7